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3 years ago

1) A cyclist travels a distance of 90 miles in 5 hours. What

Mathematics

1 answer:

Nostrana [21]3 years ago

4 0

Answer:

Step-by-step explanation: Speed is distance an object travelled per unit time.

It is represented by letter v and can assume various units.

1) $v=\frac{distance}{time}=\frac{d}{t}$

$v=\frac{90}{5}$

v = 18 miles per hour

Her average speed is 18 mph.

2) Rearraging formula for distance:

d = v.t

d = 70 * 4

d = 280 miles

You would travel 280 miles.

3) $v=\frac{d}{t}$

$v=\frac{315}{6}$

v = 52.5 mph

My average speed is 52.5 mph.

4) Rearranging formula to determine time:

$t=\frac{d}{v}$

$t=\frac{210}{90}$

t = 2.34 hours

It will take 2 hours and half to arrive in Leeds. So, we will be expected to arrive at 12:04.

5) The unit change but the way of calculating time is the same.

$t=\frac{2000}{4}$

t = 500 s

or t = 8.34 minutes

It will take, for an athlete to run 2000m, 8.34 minutes.

6) a) All units must match, so for a speed in mph:

45 minutes is 0.75 hours. Total time is 8.75 hours.

$v=\frac{420}{8.75}$

v = 560 mph

The average speed is 560 mph.

b) $t=\frac{d}{v}$

$t=\frac{420}{63}$

t = 6.67 hours

Sam will take 6.67 hours to covered the distance.

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A report on consumer financial literacy summarized data from a representative sample of 1,664 adult Americans. Based on data fro

daser333 [38]

Answer:

a. The 95% confidence interval for the proportion of all adult Americans who would give themselves a grade of A or B on their financial knowledge of personal finance is (0.54, 0.588). This means that we are 95% sure that the true proportion of all adult Americans who would give themselves a grade of A or B on their financial knowledge of personal finance is between these two bounds.

b. Because this confidence interval is entirely above 0.5, the interval is consistent with the statement that a majority of adult Americans would give themselves a grade of A or B.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

Sample of 1,664 adult Americans, 939 people in the sample would have given themselves a grade of A or B in personal finance.

This means that $n = 1664, \pi = \frac{939}{1664} = 0.5643$

95% confidence level

So $\alpha = 0.05$ , z is the value of Z that has a pvalue of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.5643 - 1.96\sqrt{\frac{0.5643*0.4357}{1644}} = 0.54$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.5643 + 1.96\sqrt{\frac{0.5643*0.4357}{1644}} = 0.588$

The 95% confidence interval for the proportion of all adult Americans who would give themselves a grade of A or B on their financial knowledge of personal finance is (0.54, 0.588). This means that we are 95% sure that the true proportion of all adult Americans who would give themselves a grade of A or B on their financial knowledge of personal finance is between these two bounds.

(b) Is the confidence interval from part (a) consistent with the statement that a majority of adult Americans would give themselves a grade of A or B?

Yes, because the confidence interval is entirely above 0.5.

Because this confidence interval is entirely above 0.5, the interval is consistent with the statement that a majority of adult Americans would give themselves a grade of A or B.

8 0

2 years ago

Solve these equation 4(3-x)=(1-2x)

serg [7]

To attempt this algebraic equation we will be multiplying 4 to (3 - x) bracket so as to form the term on L.H.S.

$:\implies\tt{4(3 - x) = (1 - 2x)}$