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Troyanec [42]
2 years ago
15

1) A cyclist travels a distance of 90 miles in 5 hours. What

Mathematics
1 answer:
Nostrana [21]2 years ago
4 0

Answer:

Step-by-step explanation: <u>Speed</u> is distance an object travelled per unit time.

It is represented by letter v and can assume various units.

1) v=\frac{distance}{time}=\frac{d}{t}

v=\frac{90}{5}

v = 18 miles per hour

Her average speed is 18 mph.

2) Rearraging formula for distance:

d = v.t

d = 70 * 4

d = 280 miles

You would travel 280 miles.

3)  v=\frac{d}{t}

v=\frac{315}{6}

v = 52.5 mph

My average speed is 52.5 mph.

4) Rearranging formula to determine time:

t=\frac{d}{v}

t=\frac{210}{90}

t = 2.34 hours

It will take 2 hours and half to arrive in Leeds. So, we will be expected to arrive at 12:04.

5) The unit change but the way of calculating time is the same.

t=\frac{2000}{4}

t = 500 s

or t = 8.34 minutes

It will take, for an athlete to run 2000m, 8.34 minutes.

6) a) All units must match, so for a speed in mph:

45 minutes is 0.75 hours. Total time is 8.75 hours.

v=\frac{420}{8.75}

v = 560 mph

The average speed is 560 mph.

b) t=\frac{d}{v}

t=\frac{420}{63}

t = 6.67 hours

Sam will take 6.67 hours to covered the distance.

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3 years ago
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Answer:

132 feet

Step-by-step explanation:

Given that Alejandro is standing at a distance of 140 feet from the base of the tree and his eyes are 6 feet above the ground.

Let AB is the height of the tree and point E is the location of his eyes which is 6 feet above from C on the ground as shown in the figure.

The distance between points A and C, AC=140 feet.

Drawing a horizontal line from point E which meets AB at point D as shown.

As ACED forms a rectangle, so

AC=DE=140 feet ...(i)

CE=AD= 6 feet ...(ii)

The height of the tree, AB=AD+DB

By using equation (ii),  AB=6+DB ...(iii)

Now, given that the on watching the top of the tree, the reading on the clinometer is 42 degrees.

So,\angle DEB = 42^{\circ}

In triangle DEB,

\tan 42^{\circ} = \frac {DB}{DE} \\\\\Rightarrow DB = DE \times \tan 42^{\circ} \\\\

\Rightarrow DB = 140 \times \tan 42^{\circ} [from (i)]

\Rightarrow DB = 126 feet

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Hence, the height of the tree is 132 feet.

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2 years ago
What is an equation of the line that passes through the point (6,1) and is
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Answer:

y - 1 = 3/2(x - 6)

Step-by-step explanation:

First, we need to find the slope of the given equation. Without a graph, the easiest way to do this is by isolating y.

2x + 3y = 18

3y = -2x + 18        (Subtract 2x from both sides)

y = -2/3x + 6        (Divide both sides by 3)

The slope is -2/3. Perpendicular lines have opposite reciprocal slopes, so a line perpendicular to this one would need to have a slope of 3/2. We're given a point for this line, so we can write the equation for it in point-slope form.

Point-Slope Form: y - y_{1}=m (x-x_{1})

y - 1 = 3/2(x - 6)

If necessary, this can also be written in slope-intercept form by solving for y.

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Answer:  Total: 30 + 20y + 85 + 17y  This is the not simplified version.

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Step-by-step explanation: I really don't know the steps.?


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