Answer:-111
Step-by-step explanation:
A \greenD{7\,\text{cm} \times 5\,\text{cm}}7cm×5cmstart color #1fab54, 7, start text, c, m, end text, times, 5, start text, c, m
erma4kov [3.2K]
Answer:
The area of the shaded region is 148.04 cm².
Step-by-step explanation:
It is provided that a 7 cm × 5 cm rectangle is inside a circle with radius 6 cm.
The sides of the rectangle are:
l = 7 cm
b = 6 cm.
The radius of the circle is, r = 6 cm.
Compute the area of the shaded region as follows:
Area of the shaded region = Area of rectangle - Area of circle
Thus, the area of the shaded region is 148.04 cm².
Step-by-step explanation:
(1) Factor the GCF out of the trinomial on the left side of the equation. (2 points: 1 for the GCF, 1 for the trinomial) 2x²+6x-20=0
2x²+6x-20
2(x²+3x-10)
the factors are 2 and (x²+3x-10)
(2) Factor the polynomial completely. (4 points: 2 point for each factor)
2(x²+3x-10)
2(x²-2x+5x-10)
2(x(x-2) + 5(x-2)) group like terms
2(x+5)(x-2)
(3) If a product is equal to zero, we know at least one of the factors must be zero. And the constant factor cannot be zero. So set each binomial factor equal to 0 and solve for x, the width of your project. (2 points: 1 point for each factor)
constant = 2 cannot be zero
the other factors are (x+5) and (x-2)
(x+5)=0 => x= -5
or
(x-2)=0 => x=2
(4) What are the dimensions of your project? Remember that the width of your project is represented by x. (2 points: 1 point for each dimension)
thank you so much, sorry if it's a little confusing!!
(it is indeed confusing, because physical dimensions cannot be negative)
The dimensions of the project (assumed a rectangle) are +2 and -5
Answer: x = 3
Step-by-step explanation:
First you need to start by adding positive 4x to both sides since the 4x is a negative. 4x + (-7x) = -3x. Then it is just simply -3x+2 = -7. Since 2 is a positive number subtract both both sides by 2. Then you should get -3x = -9. Then divide both sides by -3 and the answer is x = 3.
Answer:
182 children, 91 adults, 60 students
Step-by-step explanation:
The quantity of adults is x, then the quantity of children are 2x, the quantity of students is 333-x-2x=333-3x. The charge from all adults is 12x, students gave 7*(333-3x), children gave 5*2x=10x, the sum of all money is 2422
12x+ 7(333-3x)+10x=2422
12x+2331-21x+10x=2422
2331+x=2422
x=91- the amount of adults
1) 91*2=182- the amount of children
333-91-182= 60- the amount of students