I don't think you can as long as your not plus.
1.12 2.60 hope this helps if it is wrong then I’m sorry
Answer:
Step-by-step explanation:
(ab + bc)(ab + bc)
Simplifying
(ab + bc)(ab + bc)
Multiply (ab + bc) * (ab + bc)
(ab(ab + bc) + bc(ab + bc))
((ab * ab + bc * ab) + bc(ab + bc))
Reorder the terms:
((ab2c + a2b2) + bc(ab + bc))
((ab2c + a2b2) + bc(ab + bc))
(ab2c + a2b2 + (ab * bc + bc * bc))
(ab2c + a2b2 + (ab2c + b2c2))
Reorder the terms:
(ab2c + ab2c + a2b2 + b2c2)
Combine like terms: ab2c + ab2c = 2ab2c
(2ab2c + a2b2 + b2c2)
Hello!!
Isolate the variable by dividing each side by factors that don't contain the variable.
Your answer is 12.5.
Hope that you pass your test!!
Answer: approximately 49 feets
Step-by-step explanation:
The diagram of the tree is shown in the attached photo. The tree fell with its tip forming an angle of 36 degrees with the ground. It forms a right angle triangle,ABC. Angle C is gotten by subtracting the sum of angle A and angle B from 180(sum of angles in a triangle is 180 degrees).
To determine the height of the tree, we will apply trigonometric ratio
Tan # = opposite/ adjacent
Where # = 36 degrees
Opposite = x feets
Adjacent = 25 feets
Tan 36 = x/25
x = 25tan36
x = 25 × 0.7265
x = 18.1625
Height of the tree from the ground to the point where it broke = x = 18.1625 meters.
The entire height of the tree would be the the length of the fallen side of the tree, y + 18.1625m
To get y, we will use Pythagoras theorem
y^2 = 25^2 + 18.1625^2
y^2 = 625 + 329.88
y^2 = 954.88
y = √954.88 = 30.9 meters
Height of the tree before falling was
18.1625+30.9 = 49.0625
The height of the tree was approximately 49 feets