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tatuchka [14]
2 years ago
10

When I...

Mathematics
1 answer:
valentina_108 [34]2 years ago
4 0

Answer:

11

Step-by-step explanation:

Work backwards and reverse the operations to find the original number.

Reverse the operations for add four: 8 - 4 = 4

Reverse the operations for take the square root: 4² = 16

Reverse the operations for subtract six: 16 + 6 = 22

Reverse the operations for double the number: 22 ÷ 2 = 11

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Step-by-step explanation:

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2 years ago
Malik borrowed $1,800 from the bank at a rate of 8% simple interest per year.Over the course of three years ,how much interest d
sergij07 [2.7K]
I’m gonna say c? Good luck!
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Read 2 more answers
Show your work (?) please
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2013
Because you move the decimal three places to the right.
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3 0
3 years ago
1.) Use the quadratic formula to solve the equation. If necessary, round to the nearest hundredth .x squared minus 21 x equals n
Andrew [12]
Part 1
We are given x^2-21x=-4x. This can be rewritten as x^2-18x=0.
Therefore, a=1, b=-18, c=0.
Using the quadratic formula
     x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}=\frac{-\left(-18\right)\pm \sqrt{\left(-18\right)^2-4\left(1\right)\left(0\right)}}{2\left(1\right)}
     x=\frac{18\pm 18}{2}

The values of x are
     x_1=\frac{18-18}{2}=0
     x_2=\frac{18+18}{2}=18

Part 2
Since the values of y change drastically for every equal interval of x, the function cannot be linear. Therefore, the kind of function that best suits the given pairs is a quadratic function. 

Part 3.
The first equation is y=x^2+2.
The second equation is y=3x+20.

We have 
     x^2+2=3x+20
     x^2-3x-18=0
Factoring, we have 
     \left(x-6\right)\left(x+3\right)=0
Equating both factors to zero.
     x_1-6=0\rightarrow x_1=6
     x_2+3=0\rightarrow x_2=-3

When the value of x is 6, the value of y is 
     y=3\left(6\right)+20=38

When the value of x is -3, the value of y is 
     y=3\left(-3\right)+20=11

Therefore, the solutions are (6,38) or (-3,11)
7 0
2 years ago
I need help on this plz
balandron [24]

Answer:

(2) angle1 = 139, angle2 = 41, angle4 = 41, angle5 = 139, angle6 = 41, angle7 = 139, angle8 = 41

(3) angle1 = 150, angle2 = 30, angle4 = 30, angle5 = 150, angle6 = 30, angle7 = 150, angle8 = 30

Step-by-step explanation:

All angle are either equal to each other or supplementary.  I use corresponding angles and vertical angles to prove each of the above.

For number 3, angle 3 and angle 8 are supplementary, so they add up to 180:

8x +70 + (4x - 10) = 180

12x + 60 = 180

12x = 120

x = 10

So if x = 10, then 8x + 70 = 8(10) + 70 = 150

That means all angles are either 150 or 30 for number 3.

3 0
2 years ago
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