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Olegator [25]
3 years ago
12

If I add a proton to an atom, which of the following will change? (select all that apply) a)the type of element b)The mass of th

e atom c)The charge of the atom d)The number of neutrons)
Chemistry
1 answer:
nirvana33 [79]3 years ago
4 0
The type of element will change and the mass of the atom will change; A and B
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How many grams are in 3.40 x 10^24 molecules of CH4
Arturiano [62]

Answer:

90.37 g

Explanation:

From Avogadro Number,

1 mole of every substance contains a particle number of 6.02×10²³

From the question,

1 mole of CH₄ contains 6.02×10²³ molecules.

But,

1 mole of CH₄ has a mass of 16 g

Therefore,

16 g of CH₄ contains 6.02×10²³ molecules

Then,

Y g will contain 3.4×10²⁴ molecules

Solve for Y

Y = (16× 3.4×10²⁴)/(6.02×10²³)

Y = 90.37 g

6 0
3 years ago
What mass of KNO, will dissolve in 100 g of water at 100°C?
Sphinxa [80]

Answer:

About 170-180 grams of potassium nitrate are completely dissolved in 100 g.

Explanation:

Hello!

In this case, according to the reported solubility data for potassium nitrate at different temperatures on the attached picture, it is possible to bear out that about 170-180 grams of potassium nitrate are completely dissolved in 100 g; considering that the solubility is the maximum amount of a solute that can be dissolved in a solvent, in this case water.

Best regards!

3 0
3 years ago
If energy is transferred from a table to a block of ice moving across the table, which of the following statements is true?
nikdorinn [45]

Answer:

C???

Explanation:

6 0
3 years ago
Whiskers and beaks are two examples of _____. electroreceptors mechanoreceptors olfactory receptors photoreceptors
yawa3891 [41]

Whiskers and beaks are two examples of _____. electroreceptors mechanoreceptors olfactory receptors photoreceptors

Whiskers and beaks are two examples of olfactory receptors. An olfactory receptor is a smell receptor that contains a protein capable of binding odor molecules that plays the central role of smell.

3 0
3 years ago
Student A performed gravimetric analysis for sulfate in her unknown using the same procedures we did . Results of her three tria
Andre45 [30]

Let us first calculate the accepted value of sulfate using the molar mass of sodium sulfate.

The molar mass of sodium sulfate is 2 Na + S + 4 O = 2 (22.99) + 32.07 + 4 (16)

Molar mass of Sodium sulfate = 142.05

Molar mass of sulfate = S + 4 (O) = 32.07 + 4 (16) = 96.07

% of sulfate in sodium sulfate = (Molar mass of SO4 / Molar mass of Na2SO4) x 100

% of sulfate = (96.07/142.05) x 100

% of sulfate = 67.6%

Theoretical value for % Sulfate is 67.6%

Percent error is calculated as  

Percent Error = \left | \frac{Experimental - Theoretical}{Theoretical} \right |

Let us calculate mean for student A.

Mean for student A = (68.6 + 66.2 + 67.1) / 3 = 201.9/3 = 67.3 %

% error for student A = \left | \frac{67.3 - 67.6}{67.6} \right |

% error for student A = 0.44%

Mean for student B = (66.7 +66.6 + 66.5)/3 = 199.8 /3 = 66.6 %

% error for student B = \left | \frac{66.6 - 67.6}{67.6} \right |  

% error for student B = 1.48%

Accuracy is the closeness of experimental values to the true value. This is defined in terms of absolute and percent errors.

Since percent error for student A is lower, we can say that student A was more accurate.

The precision of the data depends on the closeness of experimental values to each other. We can see that experimental values for student B were close to each other.

Therefore we can say that student B was more precise.


8 0
3 years ago
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