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3 years ago

Can some answer thissss pleaseeee its due todayy!! ill mark brainliest!!

Mathematics

2 answers:

m_a_m_a [10]3 years ago

7 0

Answer:

1. ∠C = 90°
2. ∠B = 90°
3. ∠BAD = 90°
4. ∠ADC = 90°
5. ∠EDC = 90° - 53° = 37°
6. ∠EDF = ∠DEC = 53°
7. ∠FED = 90° - 53° = 37°
8. ∠FEA = 90° - ∠FED = 90° - 37° = 53°
9. ∠EFA = 90°
10. ∠FAE = 90° - ∠FEA = 90° - 53° = 37°
11. ∠EAB = 90° - ∠FAE = 90° - 37° = 53°
12. ∠AEB = 90° - ∠EAB = 90° - 53 = 37°

Ilya [14]3 years ago

5 0

Answer:

Answer:

90°

edc=180-90-53=37by sum of angle of triangle

edf=90-37=53

fed=cde=53alternate angle

fea=180-fae-efa=180-37-90=53

efa=180-90=90linear pair

fae=180-<e-edf=180-90-53=37

eab=90-fae=90-37=53

aeb=180-b-bae=180-90-53=37

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