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Agata [3.3K]
3 years ago
7

What kind of conditions did olaudah equiano experience aboard the ship? Use evidence from the excerpt above to support your answ

er
Mathematics
1 answer:
zmey [24]3 years ago
8 0

Answer:

Equiano responds with shock and horror to the conditions he describes aboard the slave ship on the Middle Passage. Equiano is struck by the claustrophobic conditions below decks, and describes in lurid detail the smells of sweat and human waste as well as the screams and moans of slaves confined in these awful conditions

Step-by-step explanation:

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y=3/5x+3

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3 years ago
The figure below shows two pair of congruent triangles. ΔDEF ≅ ______. ΔWXY ΔWYX ΔYWX ΔYXW
Alexandra [31]

Answer:

YXW

Step-by-step explanation:

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3 years ago
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What is the solution to the equation below. Round your answer to two
bearhunter [10]

Answer:

<h2>Hey , I will help you.</h2>

Step-by-step explanation:

Given ,

x= 3.1 ,

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6 0
3 years ago
A plane flying horizontally at an altitude of 3 miles and a speed of 500 mi/h passes directly over a radar station. Find the rat
konstantin123 [22]

Answer:

The rate at which the distance from the plane to the station is increasing is 331 miles per hour.

Step-by-step explanation:

We can find the rate at which the distance from the plane to the station is increasing by imaging the formation of a right triangle with the following dimensions:

a: is one side of the triangle = altitude of the plane = 3 miles

b: is the other side of the triangle = the distance traveled by the plane when it is 4 miles away from the station and an altitude of 3 miles

h: is the hypotenuse of the triangle = distance between the plane and the station = 4 miles                    

First, we need to find b:    

a^{2} + b^{2} = h^{2}   (1)    

b = \sqrt{h^{2} - a^{2}} = \sqrt{(4 mi)^{2} - (3 mi)^{2}} = \sqrt{7} miles

Now, to find the rate we need to find the derivative of equation (1) with respect to time:

\frac{d}{dt}(a^{2}) + \frac{d}{dt}(b^{2}) = \frac{d}{dt}(h^{2})

2a\frac{da}{dt} + 2b\frac{db}{dt} = 2h\frac{dh}{dt}

Since "da/dt" is constant (the altitude of the plane does not change with time), we have:  

0 + 2b\frac{db}{dt} = 2h\frac{dh}{dt}

And knowing that the plane is moving at a speed of 500 mi/h (db/dt):

\sqrt{7} mi*500 mi/h = 4 mi*\frac{dh}{dt}

\frac{dh}{dt} = \frac{\sqrt{7} mi*500 mi/h}{4 mi} = 331 mi/h  

Therefore, the rate at which the distance from the plane to the station is increasing is 331 miles per hour.

I hope it helps you!

4 0
3 years ago
See attached questionthe last line is N (not visible line)
algol13

The figure has reflective symmetry about a line if that line divides the figure in two similar parts, which are reflections of one another.

Notice that the two figures formed when the shape is divided by line k are not similar, since one has 7 vertices and the other just 4.

Notice that the two figures formed when the shape is divided by line m are not similar, since one has 7 vertices and the other just 4.

The line l divides the figure in two shape, one is a trapezoid and the other isn't.

Only line n divides the figure in two similar shapes.

Therefore, the correct choice is B) n only.

8 0
1 year ago
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