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lutik1710 [3]
3 years ago
5

1.) The total amount of a deposit which includes $65.00 (currency); $3.65 (coins); and checks of $43.12, $137.09, $387.90, and $

1,806.21 equals:
A.) $2,442.97.

B.) $2,563.82.

C.) $2,134.75.

D.) $2,604.76.

E.) None of these choices are correct.
Mathematics
1 answer:
Brums [2.3K]3 years ago
5 0

Answer:

The answer is A.) $2,442.97

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Simplify the expression: 4(2a)+7(-4b)+(3b-5)
Alexus [3.1K]
8a-25b-5 is the answer to ur question
8 0
3 years ago
Identify the functions that are continuous on the set of real numbers and arrange them in ascending order of their limits as x t
Studentka2010 [4]

Answer:

g(x)<j(x)<k(x)<f(x)<m(x)<h(x)

Step-by-step explanation:

1.f(x)=\frac{x^2+x-20}{x^2+4}

The denominator of f is defined for all real values of x

Therefore, the function is continuous on the set of real numbers

\lim_{x\rightarrow 5}\frac{x^2+x-20}{x^2+4}=\frac{25+5-20}{25+4}=\frac{10}{29}=0.345

3.h(x)=\frac{3x-5}{x^2-5x+7}

x^2-5x+7=0

It cannot be factorize .

Therefore, it has no real values for which it is not defined .

Hence, function h is defined for all real values.

\lim_{x\rightarrow 5}\frac{3x-5}{x^2-5x+7}=\frac{15-5}{25-25+7}=\frac{10}{7}=1.43

2.g(x)=\frac{x-17}{x^2+75}

The denominator of g is defined for all real values of x.

Therefore, the function g is continuous on the set of real numbers

\lim_{x\rightarrow 5}\frac{x-17}{x^2+75}=\frac{5-17}{25+75}=\frac{-12}{100}=-0.12

4.i(x)=\frac{x^2-9}{x-9}

x-9=0

x=9

The function i is not defined for x=9

Therefore, the function i is  not continuous on the set of real numbers.

5.j(x)=\frac{4x^2-7x-65}{x^2+10}

The denominator of j is defined for all real values of x.

Therefore, the function j is continuous on the set of real numbers.

\lim_{x\rightarrow 5}\frac{4x^2-7x-65}{x^2+10}=\frac{100-35-65}{25+10}=0

6.k(x)=\frac{x+1}{x^2+x+29}

x^2+x+29=0

It cannot be factorize .

Therefore, it has no real values for which it is not defined .

Hence, function k is defined for all real values.

\lim_{x\rightarrow 5}\frac{x+1}{x^2+x+29}=\frac{5+1}{25+5+29}=\frac{6}{59}=0.102

7.l(x)=\frac{5x-1}{x^2-9x+8}

x^2-9x+8=0

x^2-8x-x+8=0

x(x-8)-1(x-8)=0

(x-8)(x-1)=0

x=8,1

The function is not defined for x=8 and x=1

Hence, function l is not  defined for all real values.

8.m(x)=\frac{x^2+5x-24}{x^2+11}

The denominator of m is defined for all real values of x.

Therefore, the function m is continuous on the set of real numbers.

\lim_{x\rightarrow 5}\frac{x^2+5x-24}{x^2+11}=\frac{25+25-24}{25+11}=\frac{26}{36}=\frac{13}{18}=0.722

g(x)<j(x)<k(x)<f(x)<m(x)<h(x)

6 0
3 years ago
In a class of 10, there are 5 students who play soccer.
Ipatiy [6.2K]

Answer:

Step-by-step explanation: 5/10=1/2  - if one student  are chosen, who plays soccer

4/9 if then the second student are chosen, who plays soccer

1/2*4/9=2/9 the probability that both  students play soccer

3 0
2 years ago
Factorise fully 9x^2 - 16y^2
dsp73
Note: a² - b² = (a-b)(a+b)

9x² - 16y² = (3x)² - (4y)² = (3x - 4y)(3x + 4y)
4 0
3 years ago
What is the value of m?​<br><br>__°
alukav5142 [94]

Answer:

62 degrees

Step-by-step explanation:

6 0
3 years ago
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