Answer:
75% one eye, 25% two eyes (or 3:1 one eye: two eye)
Explanation:
The cross between the two trolls are shown in the attached punnett square
Ee x Ee gives 3 genotypes: EE, Ee, and ee
at a ratio of :1 EE: 2 Ee: 1 ee
Ee and EE are both one eye genotypes, so the <em>phenotype </em>is 3:1 one eye to two eye.
<h2>Density dependent </h2>
Explanation:
Density dependent inhibition is the process exhibited by most normal (anchorage dependent) animal cells in culture that stop dividing once a critical cell density is reached
The critical density is considerably higher for most cells than the density at which a mono-layer is formed
As cells become more numerous, the cell surface proteins of one cell contact the adjoining cells and they signal each other to stop dividing
Normal cells proliferate until they reach finite density but cancer cells are not sensitive to density dependent inhibition
Answer:
Defective checkpoints results in death of the cell.
Normal checkpoints make sure the cell has enough resources for cell division. Normal checkpoints ensure the cells commits apoptosis if the cell has a problem it cannot fix itself.
Answer:
Two gametes end up with 30 chromosomes, one gamete will have 31 and one will have 29.
Explanation:
During meiosis, a single diploid cell divides into four haploid cells with half the chromosome number than the parent cell.
During meiosis I, homologous chromosomes separate and the chromosome number in the two daughter cells goes down by half. During meiosis II, the "sister" chromatids separate, and the chromosome number in the respective daughter cells remains the same.
Non-disjunction of a single dyad in meiosis II causes that one of the daughter cells will have an extra chromosome, and another will be lacking one. The two other gametes will be normal.
I drew a simple example of what would happen during meiosis of a 2n=4 cell if there was non-disjunction in a single dyad during meiosis II.
