<span>f(x) = 5.05*sin(x*pi/12) + 5.15
First, you need to determine the period of the function. The period will be the time interval between identical points on the sinusoidal function. For this problem, the tide is rising and at 5.15 at midnight for two consecutive days. So the period is 24 hours. Over that 24 hour period, we want the parameter passed to sine to range from 0 to 2*pi. So the scale factor for x will be 2*pi/24 = pi/12 which is approximately 0.261799388. The next thing to note is the magnitude of the wave. That will simply be the difference between the maximum and minimum values. So 10.2 ft - 0.1 ft = 10.1 ft. And since the value of sine ranges from -1 to 1, we need to divide that magnitude by 2, so 10.1 ft / 2 = 5.05 ft.
So our function at this point looks like
f(x) = 5.05*sin(x*pi/12)
But the above function ranges in value from -5.05 to 5.05. So we need to add a bias to it in order to make the low value equal to 0.1. So 0.1 = X - 5.05, 0.1 + 5.05 = X, 5.15 = X. So our function now looks like:
f(x) = 5.05*sin(x*pi/12) + 5.15
The final thing that might have been needed would have been a phase correction. With this problem, we don't need a phase correction since at X = 0 (midnight), the value of X*pi/12 = 0, and the sine of 0 is 0, so the value of the equation is 5.15 which matches the given value of 5.15. But if the problem had been slightly different and the height of the tide at midnight has been something like 7 feet, then we would have had to calculate a phase shift value for the function and add that constant to the parameter being passed into sine, making the function look like:
f(x) = 5.05*sin(x*pi/12 + C) + 5.15
where
C = Phase correction offset.
But we don't need it for this problem, so the answer is:
f(x) = 5.05*sin(x*pi/12) + 5.15
Note: The above solution assumes that angles are being measured in radians. If you're using degrees, then instead of multiplying x by 2*pi/24 = pi/12, you need to multiply by 360/24 = 15 instead, giving f(x) = 5.05*sin(x*15) + 5.15</span>
I am pretty sure it is A Becoming warm
Since it’s moving and causing friction which makes it warm
Hope this helps
Mark me brainliest
The loudness<span> of a sound is linked to the size of the vibration which produces it. A big vibration makes a louder sound. Scientists use the word '</span>amplitude<span>' for the size of waves. For waves on water, it is easy to measure the </span>amplitude<span>.</span>
Answer:
Moment about SHOULDER ∑ τ = 3.17 N / m,
Moment respect to ELBOW Στ= 2.80 N m
Explanation:
For this exercise we can use Newton's second law relationships for rotational motion
∑ τ = I α
The moment is requested on the elbow and shoulder at the initial instant, just when the movement begins.
They indicate the angular acceleration, for which we must look for the moments of inertia of the elements involved
The mass of the forearm with the included weight is approximately 2.3 kg, with a length of about 50cm
Moment about SHOULDER
∑ τ = I α
I = I_forearm + I_sphere
the forearm can be approximated as a fixed bar at one end
I_forearm = ⅓ m L²
the moment of inertia of the mass in the hand, let's approach as punctual
I_mass = m L²
we substitute
∑ τ = (⅓ m L² + M L²) α
let's calculate
∑ τ = (⅓ 2.3 0.5² + 0.5 0.5²) 10
∑ τ = 3.17 N / m
Moment with respect to ELBOW
In this case, the arm exerts an upward force (muscle) that is about 3 cm from the elbow
Στ = I α
I = I_ forearm + I_mass
I = ⅓ m (L-0.03)² + M (L-0.03)²
let's calculate
i = ⅓ 2.3 0.47² + 0.5 0.47²
I = 0.2798 Kg m²
Στ = 0.2798 10
Στ= 2.80 N m
Answer:
the molecular formula for the gas is NO₂
Explanation:
since it contains
Nitrogen = n → 30.45%
Oxygen = o → 69.55%
and 30.45%+69.55% = 100% , then the gas only contains nitrogen and oxygen
Also we know that the proportion of oxygen over nitrogen is
proportion of oxygen over nitrogen = moles of oxygen / moles of nitrogen
since
moles = mass / molecular weight
then for a sample of 100 gr of the unknown gas
mass of oxygen = 69.55%*100 gr = 69.55 gr
mass of Nitrogen = 30.45%*100 gr = 30.45 gr
proportion of oxygen over nitrogen = (mass of oxygen/ molecular weight)/(mass of nitrogen / molecular weight of nitrogen ) = (69.55 gr/ 16 gr/mol) /( 30.45 gr /14 gr/mol) = 1.998 mol of O/ mol of N≈ 2 mol of O/ mol of N
therefore there are 2 atoms of oxygen per atom of nitrogen
thus the molecular formula for the gas is:
NO₂
