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3 years ago

Without the greenhouse effect operating in our atmosphere

Physics

2 answers:

Elena L [17]3 years ago

8 0

What do you want to know?

Please, finish your question.

:-(

rjkz [21]3 years ago

5 0

Im assuming you are asking if the greenhouse effect disappeared. To begin with, Earth would chill down to a mean temperature of -23 degrees celsius

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An object moving due to gravity can be described by the motion equation y=y0+v0t−12gt2, where t is time, y is the height at tha

Lynna [10]

Answer: 6.45 s

Explanation:

We have the following equation:

$y=y_{o}+V_{o}t-\frac{1}{2}gt^{2}$ (1)

Where:

$y=0$ is the height when the rock hits the ground

$y_{o}=75 m$ the height at the edge of the cilff

$V_{o}=20 m/s$ the initial velocity

$g=9.8 m/s^{2}$ acceleration due gravity

$t$ time

$0=75 m+(20 m/s)t-(4.9 m/s^{2})t^{2}$ (2)

Rearranging the equation:

$-(4.9 m/s^{2})t^{2} + (20 m/s)t + 75 m=0$ (3)

At this point we have a quadratic equation of the form $at^{2}+bt+c=0$ , and we have to use the quadratic formula if we want to find $t$ :

$t=\frac{-b\pm\sqrt{b^{2}-4ac}}{2a}$ (4)

Where $a=-4.9$ , $b=20$ , $c=75$

Substituting the known values and choosing the positive result of the equation:

$t=\frac{-20\pm\sqrt{20^{2}-4(-4.9)(75)}}{2(-4.9)}$ (5)

$t=6.453 s$ This is the time it takes to the rock to hit the ground

8 0

3 years ago

A light-rail commuter train accelerates at a rate of 1.35 m/s2. How long does it take to reach its top speed of 80.0 km/h, start

Len [333]

Answer:

a) 16.46 seconds.

b) 13.46 seconds

c) 2.67 m/s²

Explanation:

Acceleration = a = 1.35 m/s²

Final velocity = v = 80 km/h = $80\frac{1000}{3600}=22.22\ m/s$

Initial velocity = u = 0

Equation of motion

$v=u+at\\\Rightarrow 22.22=0+1.35t\\\Rightarrow t=\frac{22.22}{1.35}=16.46\ s$

Time taken to accelerate to top speed is 16.46 seconds.

Acceleration = a = -1.65 m/s²

Initial velocity = u = 80 km/h= $80\frac{1000}{3600}=22.22\ m/s$

Final velocity = v = 0

$v=u+at\\\Rightarrow 0=22.22-1.65t\\\Rightarrow t=\frac{22.22}{1.65}=13.46\ s$

Time taken to stop the train from top speed is 13.46 seconds

Initial velocity = u = 80 km/h= $80\frac{1000}{3600}=22.22\ m/s$

Time taken = t = 8.3 s

Final velocity = v = 0

$v=u+at\\\Rightarrow 0=22.22+a8.3\\\Rightarrow a=\frac{-22.22}{8.3}=-2.67\ m/s^2$

Emergency deceleration is 2.67 m/s²

8 0

4 years ago

Please help <br><br>formula to calculate equivalent resistance

azamat

Answer:

(Equation 10.3. 2): RS=R1+R2+R3+R4+R5=20Ω+20Ω+20Ω+20Ω+10Ω=90Ω

6 0

3 years ago

Find the ratio of the lengths of the two mathematical pendulums, if the ratio of periods is 1.5

juin [17]

Answer:

The ratio of lengths of the two mathematical pendulums is 9:4.

Explanation:

It is given that,

The ratio of periods of two pendulums is 1.5

Let the lengths be L₁ and L₂.

The time period of a simple pendulum is given by :

$T=2\pi \sqrt{\dfrac{l}{g}}$

$T^2=4\pi^2\dfrac{l}{g}\\\\l=\dfrac{T^2g}{4\pi^2}$

Where

l is length of the pendulum

$l\propto T^2$

$\dfrac{l_1}{l_2}=(\dfrac{T_1}{T_2})^2$ ....(1)

ATQ,

$\dfrac{T_1}{T_2}=1.5$

Put in equation (1)

$\dfrac{l_1}{l_2}=(1.5)^2\\\\=\dfrac{9}{4}$

So, the ratio of lengths of the two mathematical pendulums is 9:4.

3 0

3 years ago

Of the following gases, ________ will have the greatest rate of effusion at a given temperature.

klio [65]

<span>Of the following gasses, CH4 will have the greatest rate of effusion at a given temperature.</span>

5 0

3 years ago

Read 2 more answers