3 years ago

Can someone please help me

Mathematics

1 answer:

My name is Ann [436]3 years ago

3 0

Answer:

100

Step-by-step explanation:

i did the math and nailed it

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Create an equation that has exactly one real solution. 6(3x+4)-x=_x+3

OleMash [197]

Answer:

$x(x+5)=x^2-3x+8$

Step-by-step explanation:

There are infinite cases of equations with exactly one real solution. To create something worth the space, this one should suffice

$x(x+5)=x^2-3x+8$

Operating

$x^2+5x=x^2-3x+8$

Simplifying

$5x=-3x+8$

Joining like terms

$8x=8$

Solving

x=1

Testing the result

$1(1+5)=1^2-3(1)+8=>6=6$

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m_a_m_a [10]

Answer:

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Step-by-step explanation:

If you look closely there are four squares inside the figure so you get the area of one square and times it by four for the area of 16.

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Setler79 [48]

Answer:

2n(14n^2+3)=28n^4+16n I'm not sure if you meant to put the question mark between or not but I did it separately for -80^2=0 n would equal zero hope this helped

Step-by-step explanation:

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the answer you are looking for is 5d+5

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The x which achieve these statement is x=0.

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