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3 years ago

JK has endpoints located at J(15,-13) and K(-9,27) what are the coordinates of the midpoint JK.

Mathematics

1 answer:

erastovalidia [21]3 years ago

7 0

Answer:

(3, 7)

Step-by-step explanation:

The formula for calculating the midpoint of two coordinates is expressed as:

M(X, Y) = [x1+x2/2, y1+y2/2]

Given the coordinates J(15,-13) and K(-9,27), the coordinates of the midpoints is expressed as:

X = 15-9/2

X = 6/2

X = 3

Similarly,

Y = y1+y2/2

Y = -13 +27/2

Y = 14/2

Y = 7

Hence the coordinate of the midpoint is at (3, 7)

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Y=-x-4

aliina [53]

Answer:

(-4 , 0)

Step-by-step explanation:

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3 years ago

2w+w^3-1/2w^2 for w=2

mars1129 [50]

The required value is 8

How can we find value?

We will find the value by putting the value of w in the given function to get the required value.

We can find the value of given function foe w=2 as shown below:

Given, function is 2w+w^3-1/2w^2

Let A=2w+w^3-1/2w^2

for w=2

A=2(2)+(2)^3-1/2(2)^2

= 2+8-1/2(4)

=2+8-2

Hence, the required value is 8.

Learn more about function here:

brainly.com/question/875118

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8 0

1 year ago

X+y=13 and 1/2x+y=10

photoshop1234 [79]

X=6
y=7

6+7
= 13

1/2(6) + 7
= 3 +7
=10

6 0

3 years ago

-2X-10=14X-7 HELP ME

Vesnalui [34]

Answer:

x= -3/16

Step-by-step explanation:

Isolate the variable by dividing each side by factors that don't contain the variable.

3 0

2 years ago

Read 2 more answers

Please help!!!!!!!!!!!!!!

Aloiza [94]

Answer:

11.4 feet

Step-by-step explanation:

Using the right triangle formed by the tent pole, the ground and the guy rope, where the guy rope (g) is the hypotenuse.

Applying Pythagoras' identity

The square on the hypotenuse is equal to the sum of the squares on the other 2 sides.

g² = 9² + 7² = 81 + 49 = 130 ( take the square root of both sides )

g = $\sqrt{130}$ ≈ 11.4 feet

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3 years ago