Question

Which are the solutions of x^2 = 19x + 1?

Answer 1

Answer:

x = $\frac{19+\sqrt{365}}{2}, \frac{19-\sqrt{365}}{2}$

Step-by-step explanation:

1. Move everything to one side of the equation.

x^2 - 19x - 1 = 0

2. Use the quadratic formula where a = 1, b = -19, and c = -1.

x = (-b +- sqrt(b^2-4ac)) / 2a

If you plug those numbers into that formula, you will get the result listed above

Answer 2

Answer:

B

x₁ = $\frac{19-\sqrt{365}}{2}$, x₂ = $\frac{19+\sqrt{365} }{2}$

Step-by-step explanation: