Recognize that you must combine "like" terms. 5x^2y and x^2y are "like" terms.
Adding them together, you get 6x^2y.
Now add 2xy^2 to 6x^2y. These are NOT "like" terms, so you end up with
6x^2y+2xy^2 as your final answer. This answer is acceptable as is.
However, you could factor out the common factors: 2xy(3x+y).
We have to solve this quadratic equation
for n to get <em>which figure has 56 blocks</em>.

For middle term factorization, we need <em>two numbers that multiplied gives us -56 and added gives us 1 (coefficient of n).</em>
<em>Such two numbers are </em><em>8</em><em> and </em><em>-7</em><em>. We can now write,</em>
<em>
</em>
<u><em>"There is no negative figure number possible, so we disregard -8"</em></u>
Our answer is 7.
ANSWER: The 7th figure has 56 blocks.
Distance Formula: 
Apply the points: 
Solve: 
Since the square root of 218 cannot be simplified, the answer is

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Step-by-step explanation:
To divide fractions, we have to focus on 4 steps, which are:
1: Change to improper fractions
2: Keep the same
3: Change the sign to multiplication
4: Flip the 2nd fraction in the equation
So, step one:
1/3 / 4/5
Step two:
1/3 / 4/5
Step three:
1/3 x 4/5
Step four:
1/3 x 4/5 = (4 / 15)
4/15 is in simplist for.
Therefore, your answer is 4/15.
Best of Luck to you!!
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Answer:
- (c1, c2, c3) = (-2t, 4t, t) . . . . for any value of t
- NOT linearly independent
Step-by-step explanation:
We want ...
c1·f1(x) +c2·f2(x) +c3·f3(x) = g(x) ≡ 0
Substituting for the fn function values, we have ...
c1·x +c2·x² +c3·(2x -4x²) ≡ 0
This resolves to two equations:
x(c1 +2c3) = 0
x²(c2 -4c3) = 0
These have an infinite set of solutions:
c1 = -2c3
c2 = 4c3
Then for any parameter t, including the "trivial" t=0, ...
(c1, c2, c3) = (-2t, 4t, t)
__
f1, f2, f3 are NOT linearly independent. (If they were, there would be only one solution making g(x) ≡ 0.)