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2 years ago

What is the fastest motion that can be measured in any frame of reference?

Physics

1 answer:

Furkat [3]2 years ago

7 0

Answer: The answer is D: 300,000km/s

Explanation:

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The weight of an astronaut plus his space suit on the Moon is only 250 N. (a) How much does the suited astronaut weigh on Earth?

Evgesh-ka [11]

Answer:

a)1500N

b)153.06kg

Explanation:

F = ma

g(moon) = is the acceleration due to gravity on the moon

g(earth) is the acceleration due to gravity on the earth

g(moon) = 1/6g(earth)

g(earth) =6g(moon)

F(gearth) = mg(earth)

= m 6g(moon)

= 6 × 250

= 1500N

b) F(gearth) = mg(earth)

m = F /g

= 1500/9.8

= 153.06kg

3 0

3 years ago

Read 2 more answers

Which way do the players on the court rotate during a game? What happens if the players serve out of order?

tigry1 [53]

Answer:

Explanation:

on volleyballit's clockwise and What Would Happen If Someone Served Out Of Order? If the wrong player on your team serves because it's not their turn, the point and the possession of the serve will go to your opponents.

5 0

2 years ago

A gamma ray photon has an energy of 0.91 GeV. (1 GeV = 109 eV.) What is the wavelength of the gamma ray in fm? (1 fm = 10-15 m)?

anastassius [24]

Answer:

$\lambda=1.37 fm$

Explanation:

The Planck Eistein relation, states that the energy of a photon is proportional to its frequency:

$E=h\nu(1)$

h is the Plank constant.The frequency of a photon is defined as the speed of light over its wavelength:

$\nu=\frac{c}{\lambda}(2)$

Replacing (2) in (1):

$E=\frac{hc}{\lambda}\\\lambda=\frac{hc}{E}\\\lambda=\frac{(4.14*10^{-15}eV\cdot s)(3*10^8\frac{m}{s})}{0.91*10^{9}eV}\\\\\lambda=(1.37*10^{-15}m)*\frac{1fm}{10^{-15}m}\\\\\lambda=1.37 fm$

6 0

2 years ago

A tennis ball with a speed of 15.7 m/s is moving perpendicular to a wall. After striking the wall, the ball rebounds in the oppo

LiRa [457]

Answer:

-3044.848m/s^2

Explanation:

Initial velocity = 15.7 m/s (u)

Final velocity = -14.444 m/s (v) velocity after striking moving opposite direction.

Time = 0.0099 s

Average acceleration :

change in velocity/ total time

= V - U/t

= -14.444 m/s - 15.7 m/s/0.0099 s

= -30.144/0.0099 s

= -3044.848m/s^2

8 0

2 years ago

Force F acts between two charges, q1 and q2, separated by a distance d. If q1 is increased to twice its original value and the d

vodka [1.7K]

Okay, haven't done physics in years, let's see if I remember this.

So Coulomb's Law states that $F = k \frac{Q_1Q_2}{d^2}$ so if we double the charge on $Q_1$ and double the distance to $(2d)$ we plug these into the equation to find

<span> $F_{new} = k \frac{2Q_1Q_2}{(2d)^2}=k \frac{2Q_1Q_2}{4d^2} = \frac{2}{4} \cdot k \frac{Q_1Q_2}{d^2} = \frac{1}{2} \cdot F_{old}$ </span>

So we see the new force is exactly 1/2 of the old force so your answer should be $\frac{1}{2}F$ if I can remember my physics correctly.

8 0

3 years ago

Read 2 more answers