The probability of finding 2 never married
10c2*0.4^2*0.6^8=
the probability of finding 1 never married
10C1*0.4*0.6^9=
the probability of finding 0 never married
10C0*0.6^10=
the answer is all the above answers added together.
think you can do the rest of the calculation by yourself. :)
btw nCr=n!/(n-r)!r!
good luck
The number of possibilities for the first one is 50 choose 5, and the number of possibilities for the second one is 60 choose 6. Since 50 choose 5 is 2118760 and 60 choose 6 is 50063860. There are less possible outcomes for state "A" and therefore you have a higher chance of winning.
Ten to the third power / 3/10th
