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Sever21 [200]
2 years ago
13

........URGENT PLEASE HELP............

Chemistry
1 answer:
Yuri [45]2 years ago
6 0

Answer:

12.0778

Explanation:

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What is the molarity of a solution containing 501mL with 35g NaCl
Vesna [10]

Answer:

Data:

mass of solute: 35g of NaCl

m.mass of solute: 58g/mol

volume of solution: 501mL

Molarity=?

Explanation:

501ml = 0.5dm3

M= g of solute/m.mass of solute*vol of solution

M= 35/58*0.5

M=1.20

6 0
3 years ago
What would a substance that could undergo condensation polymerization most likely have? two double bonds a triple bond two aldeh
blagie [28]
The fourth option on Edgen, "two alcohol functional groups". You're welcome :)
5 0
3 years ago
Read 2 more answers
Balance the following skeleton ionic reaction, and calculate E°cell to decide whether the reaction is spontaneous: Ag(s) + Cu2+
tia_tia [17]

Answer:

2Ag(s) + Cu^2+(aq) ----------> 2Ag^+(aq) + Cu(s)

Explanation:

Ag(s)/Ag^+ (aq) is the anode as shown while Cu^2+(aq)/Cu^2(s) is the cathode.

E°cell= E°cathode -E°anode= 0.34 -0.80= -0.5V

The cell is not spontaneous as written because E°cell is negative. This implies that the electrodes of the cell must be interchanged to make the cell spontaneous.

5 0
3 years ago
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What is the pressure in a gas container that is connected to an open-end U-tube manometer if the pressure of the atmosphere is 7
Whitepunk [10]

Answer:

The pressure in the gas is 656mmHg

Explanation:

In calculating the pressure of the gas;

step 1: convert the height of the mercury arm to mmHg

9.60cm = 96.0 mmHg

step 2: convert 752 torr to mmHg

I torr is 1 mmHg

752 torr = 752mmHg

Step 3: since the level of mercury in the container is higher than the level of mercury exposed to the atmosphere, we substrate the values to obtain our pressure.

So, 752mmHg - 96mmHg = 656mmHg

The pressure in the gas container is therefore 656mmHg.

N. B : if the mercury arm is in lower position, you add.

5 0
3 years ago
Determine the acid dissociation constant for a 0.0250 M weak acid solution that has a pH of 2.37 . The equilibrium equation of i
Oksanka [162]

Answer:

For part (a): pHsol=2.22

Explanation:

I will show you how to solve part (a), so that you can use this example to solve part (b) on your own.

So, you're dealing with formic acid, HCOOH, a weak acid that does not dissociate completely in aqueous solution. This means that an equilibrium will be established between the unionized and ionized forms of the acid.

You can use an ICE table and the initial concentration ofthe acid to determine the concentrations of the conjugate base and of the hydronium ions tha are produced when the acid ionizes

HCOOH(aq]+H2O(l]⇌ HCOO−(aq] + H3O+(aq]

I 0.20 0 0

C (−x) (+x) (+x)

E (0.20−x) x x

You need to use the acid's pKa to determine its acid dissociation constant, Ka, which is equal to

3 0
2 years ago
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