Answer: Concentration of N₂ is 4.8.
M.
Explanation: 
is a constant of equilibrium and it is dependent of the concentrations of the reactants and the products of a balanced reaction. For
N2(g) + 2 O2(g) ⇄ 2 NO2(g)
= ![\frac{[NO2]^{2} }{[N2][O2]^{2} }](https://tex.z-dn.net/?f=%5Cfrac%7B%5BNO2%5D%5E%7B2%7D%20%7D%7B%5BN2%5D%5BO2%5D%5E%7B2%7D%20%7D)
From the question concentration of NO2 is twice of O2:
[NO2] = 2[O2]
Substituting this into :
= ![\frac{[2O2]^{2} }{[N2][O2]^{2} }](https://tex.z-dn.net/?f=%5Cfrac%7B%5B2O2%5D%5E%7B2%7D%20%7D%7B%5BN2%5D%5BO2%5D%5E%7B2%7D%20%7D)
8.3.
= ![\frac{4O2^{2} }{[N2].O2^{2} }](https://tex.z-dn.net/?f=%5Cfrac%7B4O2%5E%7B2%7D%20%7D%7B%5BN2%5D.O2%5E%7B2%7D%20%7D)
[N2] = 
[N2] = 
[N2] = 4.8.
The concentration of N2 in the equilibrium is [N2] = 4.8.M.
Answer:
of water at 30C and 1 atm is 256.834 J/mol·K.
Explanation:
To solve the question, we note the Maxwell relation such as
Where:
= Specific heat of gas at constant pressure = 75.3 J/mol·K
= Specific heat of gas at constant volume = Required
T = Temperature = 30 °C = 303.15 K
α = Linear expansion coefficient = 3.04 × 10⁻⁴ K⁻¹
K = Volume comprehensibility = 4.52 × 10⁻⁵ atm⁻¹
Therefore,
75.3 - 
= 
= - 75.3 = 256.834 J/mol·K.
Answer:
2.12atm
Explanation:
Boyle's Law: P1V1 = P2V2
Manipulate to solve for unknown: P2 = P1V1/V2
Substitute values: P2=(1.2atm)(4.6L)/2.6L
P2 = 2.1230769atm
Round to 3 sig figs to get 2.12atm
Atomic reaction is nothing but the reaction of one atom with the other atom to form the new compound.
<u>Explanation:</u>
- The atom is considered as the ultimate basic particle of the matter.
- This atom comprise of electron neutrons and protons.
- Generally in the atomic reaction, there will be loss or gain of the electron to or from the substance with which the reaction takes place.
- In default, all atoms wanted to attain the noble gas configuration which is stable in nature. These atoms from the ionic or covalent bond by sharing the electron.
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