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3 years ago

How can a atom help you see both unity and diversity

Chemistry

1 answer:

Mariana [72]3 years ago

5 0

Atoms show us the basic proverb about the strength and the bond when they are Unity and Diversified.

<u>Explanation:</u>

Every basic matter in the earth is composed of atoms. It is the smallest unit of the matter which is taken to observe the properties of the whole element.
The atom consists of different energy levels and consist of protons electrons and neutrons.
The atoms when are compactly arranged it result in the great strength required to bring the deformation in shape which shows that unity is always great.
But in the liquid and gas, the atoms are arranged in a randomly dispersed pattern which shows that they can be separated and involved in any process easier to get the heterogeneous product easily which is an example for Diversity.

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How accurate are heist movies where the robbers throw a bunch of gold bars in a bag and carry it out of the bank? Very, because

Oduvanchick [21]

Answer:

Not very, because gold is too heavy to carry many bars at once.

Explanation:

Such movies are far from being accurate.

<em>A standard gold bar weighs about 12.4 kilograms, an equivalence of approximately 27 pounds or 437 ounces, in real life. Hence, a bunch of gold bars would weigh far more than what one person can just lift up, throw, or carry as if it is a bunch of cotton wool. </em>

The correct answer is, therefore, that <u>such movies are far from reality because gold is too heavy to carry many bars at once</u>.

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3 years ago

Consider the following reaction at equilibrium: 2CO2 (g) ↔ 2CO (g) + O2 (g) ∆H° = -514 kJ Le Châtelier's principle predicts that

Elza [17]

<h3><u>Answer;</u></h3>

increase the partial pressure of CO2

<h3><u>Explanation;</u></h3>

2CO(g) + O2(g) -------> 2CO2(g) + heat

Removel of Oxygen makes the equilibrium to move towards the left side (reactants) because the reactants concentration is decreasing. According to the LeChâtelier’s principle equilibrium moves towards the lower concentration.
When the partial pressure of any of the gaseous reactants or of the products is increased, the position of equilibrium is shifted so as to decrease its partial pressure. In this case, the removal of oxygen causes a shift to to the left which causes an increase in the partial pressure of CO2.

6 0

3 years ago

Read 2 more answers

explain in terms of collision theory, how and why a reactions's rate changes as the reaction progresses

Reptile [31]

The rate of a chemical reaction is the speed with which the reactants are converted to products while the collision theory is used to explain why chemical reactions occur at different rates. It states that for a reaction to proceed, the reactants particles must collide and the more successful collisions there are per unit of time, the faster the reaction will be. As the reaction progresses, the products builds up in the system and the chance that the reactants will collide amongst themselves reduces as the product molecules begin to build up while the molecules of the reactants are deprived. therefore the rate of reaction changes.

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3 years ago

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A sample of solid ammonium chloride decomposes on heating

elena55 [62]

$∣αηsωεя∣: −$

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2 years ago

Menthol, the substance we can smell in mentholated cough drops, is composed of c, h, and o. a 9.045×10−2 −mg sample of menthol i

Ket [755]

Answer:

Empirical Formula = C₁₀H₂₀O

Solution:

Data Given:

Mass of Menthol = 9.045 × 10⁻² mg = 9.045 × 10⁻⁵ g

Mass of CO₂ = 0.2546 mg = 0.0002546 g

Mass of H₂O = 0.1043 mg = 0.0001043 g

Step 1: Calculate %age of Elements as;

%C = (mass of CO₂ ÷ Mass of sample) × (12 ÷ 44) × 100

%C = (0.0002546 ÷ 9.045 × 10⁻⁵) × (12 ÷ 44) × 100

%C = (2.814) × (12 ÷ 44) × 100

%C = 2.814 × 0.2727 × 100

%C = 76.73 %

%H = (mass of H₂O ÷ Mass of sample) × (2.02 ÷ 18.02) × 100

%H = (0.0001043 ÷ 9.045 × 10⁻⁵) × (2.02 ÷ 18.02) × 100

%H = (1.153) × (2.02 ÷ 18.02) × 100

%H = 1.153 × 0.1120 × 100

%H = 12.91 %

%O = 100% - (%C + %H)

%O = 100% - (76.73% + 12.91%)

%O = 100% - 89.64%

%O = 10.36 %

Step 2: Calculate Moles of each Element;

Moles of C = %C ÷ At.Mass of C

Moles of C = 76.73 ÷ 12.01

Moles of C = 6.3888 mol

Moles of H = %H ÷ At.Mass of H

Moles of H = 12.91 ÷ 1.01

Moles of H = 12.7821 mol

Moles of O = %O ÷ At.Mass of O

Moles of O = 10.36 ÷ 16.0

Moles of O = 0.6475 mol

Step 3: Find out mole ratio and simplify it;

C H O

6.3888 12.7821 0.6475

6.3888/0.6475 12.7821/0.6475 0.6475/0.6475

9.86 19.74 1

≈ 10 ≈ 20 1

Result:

Empirical Formula = C₁₀H₂₀O₁

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4 years ago