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9966 [12]
3 years ago
12

Can someone list these in correct order? from least brigehst to brightest?​

Chemistry
1 answer:
Setler79 [48]3 years ago
8 0
Polaris -least brightest
Pluto
Venus
Moon
Sun - most brightest
You might be interested in
How many scientific methods
iogann1982 [59]

Answer:

There is one scientific method

it starts with an

OBSERVATION

then a HYPOTHESIS

which goes to planning, creating an EXPERIMENT

and finally a conclusion for your results

Explanation:

8 0
3 years ago
How much CO2 is produced from the combustion of a tank of propane C3H8? Assume the tank contains 9kgs of propane and the molecul
Zinaida [17]

<u>Answer:</u> The mass of carbon dioxide produced is 26.9 kg

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}      .....(1)

Given mass of propane = 9 kg = 9000 g    (Conversion factor:  1 kg = 1000 g)

Molar mass of propane = 44.1 g/mol

Putting values in equation 1, we get:

\text{Moles of propane}=\frac{9000g}{44.1g/mol}=204.08mol

The chemical equation for the combustion of propane follows:

C_3H_8+5O_2\rightarrow 3CO2+4H_2O

By Stoichiometry of the reaction:

1 mole of propane produces 3 moles of carbon dioxide.

So, 204.08 moles of propane will produce = \frac{3}{1}\times 204.08=612.24mol of carbon dioxide.

Now, calculating the mass of carbon dioxide by using equation 1, we get:

Molar mass of carbon dioxide = 44.01 g/mol

Moles of carbon dioxide = 612.24 moles

Putting values in equation 1, we get:

612.24mol=\frac{\text{Mass of carbon dioxide}}{44.01g/mol}\\\\\text{Mass of carbon dioxide}=(612.24mol\times 44.01g/mol)=26944.7g=26.9kg

Hence, the mass of carbon dioxide produced is 26.9 kg

3 0
3 years ago
What physical properties are important for the materials used to make mountain bikes?
Nikitich [7]

Answer:

density, yield strength, elasticity, Ductility, toughness, fatigue limit and corrosion resistance

7 0
3 years ago
A 250.0-mL buffer solution initially contains 0.025 mol of HCHO2 and 0.025 mol of NaHCO2. In order to adjust the buffer pH to 4.
worty [1.4K]

Answer:

We need to add NaOH to increase the pH decreasing the H⁺ concentration.

0.4g of NaOH must be added

Explanation:

The pKa of HCHO2 is 3.74. Using H-H equation the initial pH of the buffer is:

pH = pKa + log [NaHCO2] / [HCHO2]

pH = 3.74 + log [0.025mol] / [0.025mol]

pH = 3.74

The initial pH is 3.74, as we want a pH of 4.10, <em>we need to add NaOH to increase the pH decreasing the H⁺ concentration.</em>

<em></em>

Total moles of HCHO2-NaHCO2 buffer are:

0.025mol + 0.025mol =

0.050mol = [HCHO2] + [NaHCO2] <em>(1)</em>

Using H-H equation:

4.10 = 3.74 + log [NaHCO2] / [HCHO2]

0.36 = log [NaHCO2] / [HCHO2]

2.29087 = [NaHCO2] / [HCHO2] <em>(2)</em>

<em></em>

NaOH reacts with HCHO2 as follows:

NaOH + HCHO2 → NaHCO2 + H2O

Replacing (1) in (2):

2.29087 = 0.050 - [HCHO2] / [HCHO2]

2.29087[HCHO2]  = 0.050 - [HCHO2]

3.29087[HCHO2]  = 0.050

[HCHO2] = 0.015 moles

As HCHO2 decreases from 0.025 moles to 0.015 moles, the moles of NaOH added are 0.010moles.

The mass is:

0.010moles NaOH * (40g/mol) =

<h3>0.4g of NaOH must be added</h3>
5 0
3 years ago
For production of crude biodiesel from 250,000 kg/h rapeseed oil reacted with 75,000 kg/h ethanol and 250 kg/h potassium hydroxi
Tanya [424]

Answer:

will be 237,500 kg/h

Explanation:

The necessary ingredients to produce the biodiesel from the plant are: the plant, ethanol and the base. So after a period of 1 hour, the biodiesel that is going to be formed is 237, 500 kg/h.

Just apply the rule of three to the main source of biodiesel, that in this case is the rapessed plant and apply the 95 %. Ex:

Biodiesel = 0.95 x 250,000 = 237,500 kg/h

7 0
4 years ago
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