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Kay [80]
3 years ago
9

Can someone shorten these definitions?

Chemistry
1 answer:
rodikova [14]3 years ago
5 0
A good night to see him again soon as I have to work tomorrow morning and I’m just gonna let go out and get it out and then I’ll head out and I can do that and then I’ll
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The average person in the United States is exposed to the following amount of radiations annually. Rank the following source of
Papessa [141]
<span>#1 is air radon, #2 is x-ray, #3 is ground, #4 is cosmic radiation, #5 is TV tube, #6 is weapons test fallout . That's all I got hope I helped!</span>
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3 years ago
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6. A. If 4.50 mols of ethane, C2H6, undergoes combustion according to the unbalanced equation
uranmaximum [27]

Answer:

for one mole of C2H6 there are 7/2 mole of O2 required. so for4. 50 moles you require 4.50 x 7/2 = 15.75 moles of O2.

Explanation:

i hope it's helpful

6 0
3 years ago
Why was alchemy so confusing?​
galina1969 [7]
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Alchemy is extremely complicated. It is based on the practical skills of early metal workers and craftsmen, on Greek philosophy, and on Eastern mystic cults that sprang up in the first centuries after Christ and influenced so much of magic and occult thought.
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3 years ago
[11]. Of these four liquids, which is the most viscous?
-Dominant- [34]
The most viscous among the choices is D. Honey at room temperature.

Viscosities of liquids typically vary with temperature. The higher the temperature, the lower the viscosity. Among the choices, only motor oil and honey appear to be the most viscous. The clue that helps determined the answer are the words "hot" and "room temperature". Hot motor oil is less viscous, while honey at room temperature is more viscous. Even comparing their viscosities at room temperature, honey already has a higher viscosity than motor oil.
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3 years ago
In the molecules below, areas that have a partial negative charge are pink and areas that have a partial positive charge are blu
Kaylis [27]

Answer:

Dipole-dipole interactions

Step-by-step explanation:

Each molecule consists of <em>two different elements</em>.

Thus, each molecule has permanent <em>bond dipoles</em>.

The dipoles do not cancel, so the attractive forces are dipole-dipole attractions.

"Covalent bonds" is <em>wrong,</em> because there are no bonds between the two molecules.

There are dipole-induced dipole and London dispersion forces, but they are much weaker than the dipole-dipole attractions.

4 0
3 years ago
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