Hello!
1) What is the limiting reactant?The chemical equation for this reaction is:
2Al(OH)₃ → Al₂O₃ + 3H₂OThe
Limiting Reactant is the one that is in the lowest amount in the reaction and determines how many moles are produced. You can see that in this chemical equation there is only one reactant since this reaction is a
decomposition reaction. So,
the limiting reactant is Al(OH)₃.2) How many grams of water are produced?The chemical equation for this reaction is:
2Al(OH)₃ → Al₂O₃ + 3H₂O
So, we are going to use the following conversion factor to go from grams of Al(OH)₃ to grams of water:
So,
6,17 grams of Water are produced.
Have a nice day!
The environment affects natural selection. Speices need to adapt to changes in environmnet. The weaker organisms which fail to adapt to environment perish while the stronger ones who adapt to the environment survive. This is how environment affects natural selection.
Answer:
% = 76.75%
Explanation:
To solve this problem, we just need to use the expressions of half life and it's relation with the concentration or mass of a compound. That expression is the following:
A = A₀ e^(-kt) (1)
Where:
A and A₀: concentrations or mass of the compounds, (final and initial)
k: constant decay of the compound
t: given time
Now to get the value of k, we should use the following expression:
k = ln2 / t₁/₂ (2)
You should note that this expression is valid when the reaction is of order 1 or first order. In this kind of exercises, we can assume it's a first order because we are not using the isotope for a reaction.
Now, let's calculate k:
k = ln2 / 956.3
k = 7.25x10⁻⁴ d⁻¹
With this value, we just replace it in (1) to get the final mass of the isotope. The given time is 1 year or 365 days so:
A = 250 e^(-7.25x10⁻⁴ * 365)
A = 250 e^(-0.7675)
A = 191.87 g
However, the question is the percentage left after 1 year so:
% = (191.87 / 250) * 100
<h2>
% = 76.75%</h2><h2>
And this is the % of isotope after 1 year</h2>
A solution with hydroxide ion concentration of 4.15 x10^-6 m is basic and has a hydrogen ion concentration of 2.41 x10^-9 M
we well know thaat (H^+) (OH^-) = 1 x10^-14
by making H^+ concentration the subject of the formula
H^+ = 1 x10^-14/OH^-
H^+= 1 x10^-14/4.15 x10^-6 = 2.41 x10^-9 M
the solution is basic since OH^- ion is for basic solution
Explanation:
The prefix inter- means between, reflecting that interphase takes place between one mitotic (M) phase and the next. Image of the cell cycle. Interphase is composed of the G1 phase (cell growth), followed by the S phase (DNA synthesis), followed by the G2 phase (cell growth).