Answer:
The minor arc HK is 60 degrees
Step-by-step explanation:
see the attached figure to better understand the problem
we know that
The inscribed angle is half that of the arc it comprises.
so
![m\angle HLK=\frac{1}{2}(arc\ HK)](https://tex.z-dn.net/?f=m%5Cangle%20HLK%3D%5Cfrac%7B1%7D%7B2%7D%28arc%5C%20HK%29)
we have
![m\angle HLK=30^o](https://tex.z-dn.net/?f=m%5Cangle%20HLK%3D30%5Eo)
substitute the given value
![30^o=\frac{1}{2}(arc\ HK)](https://tex.z-dn.net/?f=30%5Eo%3D%5Cfrac%7B1%7D%7B2%7D%28arc%5C%20HK%29)
![arc\ HK=60^o](https://tex.z-dn.net/?f=arc%5C%20HK%3D60%5Eo)
Remember that the measure of the minor arc must be less than 180 degrees
therefore
The minor arc HK is 60 degrees
False because it’s not correct it’s a false statement because (again)…
I am pretty sure number 3 is the right answer
Your're lucky am going to help. Kidding. :D
All real numbers but 3 and -3
Using the sum (addition) and two 2-digit addends, 12 + 34 can be answered without regrouping.