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tatuchka [14]
3 years ago
14

Please help me now! I will give brainly

Mathematics
2 answers:
olga2289 [7]3 years ago
7 0
1) 15
2)6
3)9
Hope this helps!
insens350 [35]3 years ago
5 0
Orange is 6, blue is 9 and yellow is 15
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How many centimeters are in 5 inches? 1in. = 2.54 cm<br><br> 5 in. = ?
Aleks [24]
It is very simple the answer is 12.7 cm
You can simply multiply 5 with 2.54 to get the answer
Hope it helps : )
6 0
3 years ago
What number gives a result of -8 when 11 is subtracted from the quotient of the number and 6?
forsale [732]

Answer:

18

Step-by-step explanation:

The formula X/6 - 11 = -8

Add 11 to both sides of the equation X/6 = 3

Multiply by 6 both sides to cancel out the division

X = 18

3 0
3 years ago
sue has a monthly budget of 4300 after she gets done paying bills she usually has about 3% of the money left for random items ho
LuckyWell [14K]
You have to take 3% of 4300 which is $129.
6 0
3 years ago
Answer this question on the picture
vaieri [72.5K]

Answer:

When one variable influences a change in another

Step-by-step explanation:

Causation means that one event causes another event to occur.

3 0
3 years ago
What is the probability that the mean duration of the 24 rowers with idna exceeds 63 minutes?
statuscvo [17]

Answer:

Step-by-step explanation:

Given that: Training-session duration of female rowers with normal iron status is Normally distributed, with mean 69 minutes and standard deviation 18minutes.

Solution:

z score shows the relationship between sample means. The z score is used to determine by how many standard deviations the raw score is above or below the mean. It is given by the formula:

z=\frac{x-\mu}{\sigma}\\\\for\ sample(n):\\\\z=\frac{x-\mu}{\sigma/\sqrt{n} }  \\\\where\ \mu=mean,\sigma=standard\ deviation,x=raw\ score

Given that μ = 69 minutes, σ = 18 minutes, n = 24

For x > 63 minutes:

z=\frac{x-\mu}{\sigma / \sqrt{n} } =\frac{63-69}{18/\sqrt{24} }=-1.63

From the distribution table, P(x > 63) = P(z > -1.63) = 1 - P(z < 1.63) = 1 - 0.0516 = 0.9484

7 0
3 years ago
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