Answer:
4489
Step-by-step explanation:
96/2 for tails and 96/6 for rolling 4 I assume
The probability that at least one of them has an injection-site reaction is: 0.5356.
<h3>
Probability</h3>
Using this formula
Probability of atleast one= 1- (1- Proportion)^n
Where:
Proportion=.12
Sample size=n=6
Let plug in the formula
Probability of atleast one=1-(1-.12)^6
Probability of atleast one=1-(.88)^6
Probability of atleast one=1-.4644041
Probability of atleast one=0.53559
Probability of atleast one=0.5356 (Approximately)
Therefore the probability that at least one of them has an injection-site reaction is: 0.5356.
Learn more about probability here:brainly.com/question/20411748
#SPJ1
3 and what?
if it is 3 and 5 than the answer would be 15
Answer:
x = 12
y = 4.5
Step-by-step explanation:
Since ∆FGH ~ ∆KLJ, therefore, we would have the following proportion:
![\frac{FG}{KL} = \frac{GH}{LJ} = \frac{FH}{KJ}](https://tex.z-dn.net/?f=%20%5Cfrac%7BFG%7D%7BKL%7D%20%3D%20%5Cfrac%7BGH%7D%7BLJ%7D%20%3D%20%5Cfrac%7BFH%7D%7BKJ%7D%20)
![\frac{9}{y} = \frac{x}{6} = \frac{6}{3}](https://tex.z-dn.net/?f=%20%5Cfrac%7B9%7D%7By%7D%20%3D%20%5Cfrac%7Bx%7D%7B6%7D%20%3D%20%5Cfrac%7B6%7D%7B3%7D%20)
✔️Let's solve for x using:
![\frac{x}{6} = \frac{6}{3}](https://tex.z-dn.net/?f=%20%5Cfrac%7Bx%7D%7B6%7D%20%3D%20%5Cfrac%7B6%7D%7B3%7D%20)
Multiply both sides by 6
![\frac{x}{6}*6 = \frac{6}{3}*6](https://tex.z-dn.net/?f=%20%5Cfrac%7Bx%7D%7B6%7D%2A6%20%3D%20%5Cfrac%7B6%7D%7B3%7D%2A6%20)
![x = \frac{6*6}{3}](https://tex.z-dn.net/?f=%20x%20%3D%20%5Cfrac%7B6%2A6%7D%7B3%7D%20)
![x = 12](https://tex.z-dn.net/?f=%20x%20%3D%2012%20)
✔️Solve for y using:
![\frac{9}{y} = \frac{6}{3}](https://tex.z-dn.net/?f=%20%5Cfrac%7B9%7D%7By%7D%20%3D%20%5Cfrac%7B6%7D%7B3%7D%20)
Cross multiply
![y*6 = 3*9](https://tex.z-dn.net/?f=%20y%2A6%20%3D%203%2A9%20)
6y = 27
y = 27/6
y = 4.5