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Maksim231197 [3]
2 years ago
12

16.750)

Mathematics
1 answer:
Mama L [17]2 years ago
4 0

Answer:

es no me interesa hací que nose

Step-by-step explanation:

<h3>145681257622467323775322367777777</h3>
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Gabriela 30 in of ribbon to make bows each bow uses 5 in of ribbon how many ribbons dose Gabriela make
Shalnov [3]

Answer:

Gabriela Can Make 6 Bows.

Step-by-step explanation:

30 ÷ 5 = 6

So Gabriela Has Enough Ribbon To Make 6 Bows.

3 0
2 years ago
Fill in the blank with a constant, so that the resulting expression can be factored as the product of two linear expressions: 2a
Vitek1552 [10]

Answer:

2ab - 6a + 5b - 15

Step-by-step explanation:

Given

2ab - 6a + 5b + \_

Required

Fill in the gap to produce the product of linear expressions

2ab - 6a + 5b + \_

Split to 2

(2ab - 6a) + (5b + \_)

Factorize the first bracket

2a(b - 3) + (5b + \_)

Represent the _ with X

2a(b - 3) + (5b + X)

Factorize the second bracket

2a(b - 3) + 5(b + \frac{X}{5})

To result in a linear expression, then the following condition must be satisfied;

b - 3 = b + \frac{X}{5}

Subtract b from both sides

b - b- 3 = b - b+ \frac{X}{5}

- 3 = \frac{X}{5}

Multiply both sides by 5

- 3 * 5 = \frac{X}{5} * 5

X = -15

Substitute -15 for X in 2a(b - 3) + 5(b + \frac{X}{5})

2a(b - 3) + 5(b + \frac{-15}{5})

2a(b - 3) + 5(b - \frac{15}{5})

2a(b - 3) + 5(b - 3)

(2a + 5)(b - 3)

The two linear expressions are (2a+ 5) and (b - 3)

Their product will result in 2ab - 6a + 5b - 15

<em>Hence, the constant is -15</em>

3 0
3 years ago
Question 4
Hunter-Best [27]
So uh uhm yes uhhhhhhhhhhhhhhhh
4 0
2 years ago
Read 2 more answers
Write 2.7 as a fraction or mixed number
Elden [556K]

Answer: 2 \frac{7}{10}

Step-by-step explanation: Using the place value chart we can see that 2.7 means two and seven-tenths which can be written as the mixed number

2 \frac{7}{10}.

5 0
3 years ago
Prove algebraically that 8.99999... = 9
Jobisdone [24]
You can't, it has been done before but there is a fault in the working because the 2 numbers are different. If you want to see a video of someone attempt it, I believe there is a video on the numberphile channel.

Hope this helps :)
5 0
2 years ago
Read 2 more answers
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