Find [h(x) +m(x)]-[h(x)-m(x)] H(x)=1/3x3/3 3x2+9x-2 M(x)=13 3/5x+6x3-2x2-4x

Mathematics

1 answer:

Andre45 [30]3 years ago

7 0

Answer:

\frac{276}{5}-8x)

Step-by-step explanation:

We are given with

H(x)=1/3x3/3 3x2+9x-2

And

M(x)=13 3/5x+6x3-2x2-4x

And asked to determine

[h(x) +m(x)]-[h(x)-m(x)]

Opening the second parenthesis

h(x) +m(x)-h(x)+m(x)

As we subtracted the second bracket, the sign get reversed.

As h(x) has opposite signs , they get cancelled

h(x) +m(x)-h(x)+m(x)

=2m(x)

=2(13\tfrac{3}/{5}x+6x3-2x2-4x)

=2(\frac{13 \times 5 + 3}{5}+18-4-4x)

=2(\frac{68}{5}+14-4x)

=2(\frac{68+70}{5}-4x)

=2(\frac{138}{5}-4x)

=\frac{276}{5}-8x)

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