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masha68 [24]
3 years ago
14

PLEASE HELP!!!!I IM GIVING BRAINLIEST!! If you answer this correctly ill answer some of your questions you have posted! (30pts)

Physics
1 answer:
maksim [4K]3 years ago
6 0

<em>Kinetic Energy</em>

=><em><u>It is defined as the work needed to accelerate a body of a given mass from rest to its stated velocity.</u></em>

<em>Potential</em><em> </em><em>Energy</em><em> </em>

<u><em>=</em><em>></em><em>potential energy is the energy held by </em></u><em><u>an</u></em>

<em><u> object because of its position relative to </u></em><em><u>other</u></em>

<em><u> objects, stresses within itself, its </u></em><em><u>electric</u></em>

<em><u> charge, or other factors.</u></em>

<h2>Difference:</h2>

=>Potential energy is a <u>stored</u> energy on the other hand kinetic energy is the energy of an object or a system's particle in <em><u>Motion</u></em>.

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Is it safe to drive your 1600-kg car at speed 34 m/s around a level highway curve of radius 190 m if the effective coefficient o
adoni [48]

Answer:

It is unsafe

Explanation:

v = Velocity of car = 34 m/s

r = Radius of turn = 190 m

\mu = Coefficient of static friction = 0.5

m = Mass of car = 1600 kg

g = Acceleration due to gravity = 9.81 m/s²

The centripetal force is given by

F_c=m\frac{v^2}{r}\\\Rightarrow F_c=1600\frac{34^2}{190}\\\Rightarrow F_c=9734.73\ N

The frictional force is given by

F_f=\mu mg\\\Rightarrow F_f=0.5\times 1600\times 9.81\\\Rightarrow F_f=7848\ N

If the centripetal force is greater than the frictional force then the car will slip which makes it unsafe.

Here, the centripetal force is greater than the frictional force which makes it unsafe to drive it at that speed.

4 0
3 years ago
Write the similarity between the inclined plane and a screw?​
lord [1]

An inclined plane makes work easier by breaking an upward or downward movement into smaller increments.

A screw is like an inclined plane wrapped around a cylinder. It turns a small rotational force into a larger forward driving force

7 0
3 years ago
If the input force on a simple machine is 2 N and the output force is 4 N, what is it’s mechanical advantage?
ivann1987 [24]

Explanation:

Given that,

Input force on a simple machine, F = 2 N

The output force on a simple machines, F' = 4 N

The ratio of the output force to the input force of any simple machines is called its mechanical advantage. Mathematically, it is given by :

m=\dfrac{F'}{F}

Putting the value of F and F' in above equation. We get :

m=\dfrac{4}{2}

m = 2

So, the mechanical advantage of the simple machines is 2. Hence, this is the required solution.

7 0
3 years ago
Read 2 more answers
I want to make a Twinkie splat when I throw it off a building. Because Twinkies are notoriously hard to crush, I want it to hit
Monica [59]

Answer:

s=253.6524712 \approx 253.7

Explanation:

From the question we are told that

Initial speedv=8ft/s

Final speed v=128ft/s

Generally the Newtons  equation of motion is mathematically represented by

V_f^2-V_0^2=2as

with

Therefore

a=g=>9.81m/s^2\\a=32.17ft/s^2

Therefore

128^2-8^2=2*(32.17)*s

16320=2*(32.17)*s

s=\frac{16320}{2*(32.17)}

s=253.6524712 \approx 253.7

3 0
3 years ago
Ron weighs a bottle with a mass of 0.5 kilograms on a spring scale. The spring stretches by 1 centimeter. He then weighs a secon
Yuri [45]

Answer:

1 kg

Explanation:

Applying,

Hook's law,

F = ke................. Equation 1

Where F = force, k = force constant of the spring, e = extension.

But from the question,

The weight of the bottle is the force acting on the spring scale

therefore,

mg = ke............ Equation 2

Where m = mass of the bottle, g = acceleration due to gravity.

make k the subject of the equation

k = mg/e............ Equation 3

Given: m = 0.5 kg, e = 1 cm = 0.01 m

Constant: g = 9.8 m/s²

k = (0.5×9.8)/0.01

k = 490 N/m

If the mass of the second bottle is weighed,

given: e = 2 cm = 0.02 m

subtitute into equation 1

m×9.8 = 490×0.02

9.8m = 9.8

m = 9.8/9.8

m = 1 kg.

Hence the mass of the second bottle is 1 kg

5 0
3 years ago
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