i guess that would be false cause ...
the elements in periodic table are arranged by atomic number which is basically the number of protons
hope that helps :)
Answer:
The magnitude of the emf induced in the coil is 60 mV.
Explanation:
We have,
Side of the square coil, a = 24 cm = 0.24 m
Number of turns in the coil, N = 2
It is placed in a uniform magnetic field that makes an angle of 60 degrees with the plane of the coil. If the magnitude of this field increases by 6.0 mT every 10 ms, we need to find the magnitude of the emf induced in the coil.
We know that the induced emf is given by the rate of change of magnetic flux throughout the coil. So,

is the angle between magnetic field and the normal to area vector.
But in this case, a uniform magnetic field that makes an angle of 60 degrees with the plane of the coil. So, the angle between magnetic field and the normal to area vector is 90-60=30 degrees.
Now, induced emf becomes :

or

So, the magnitude of the emf induced in the coil is 60 mV. Hence, this is the required solution.
You would multiply the speed by the time. So the answer would be 840 miles.
By v = u - at
<span>=>8 = 12 - a x 0.25 </span>
<span>=>a = 4/0.25 km/hr/sec </span>
<span>=>a = 16km/hr/sec
I hope this helped!</span>
(1) Changing Fahrenheit to Celsius:
The formula used to convert from Fahrenheit to Celsius is as follows:
C = <span>(F - 32) * 5/9
</span>We are given that F=200, substitute in the above formula to get the corresponding temperature in Celsius as follows:
C = (200-32) * (5/9) = 93.333334 degrees Celsius
(2) Changing the Fahrenheit to kelvin:
The formula used to convert from Fahrenheit to kelvin is as follows:
K = <span>(F - 32) * 5/9 + 273.15
</span>We are given that F = 200. substitute in the above formula to get the corresponding temperature in kelvin as follows:
K = (200-32)*(5/9) + 273.15 = 366.483334 degrees kelvin