A slanted surface used to raise an object is a(n)

Name two processes that release nuclear energy?

Kaylis [27]

Answer: Nuclear energy is released from an atom through one of two processes: nuclear fusion or nuclear fission. In nuclear fusion, energy is released when the nuclei of atoms are combined or fused together. This is how the sun produces energy. In nuclear fission, energy is released when the nuclei of atoms are split apart.

Let me know if it helps!

7 0

3 years ago

The temperature decreases 5°C in one hour and then decreases another 3°C in the next hour. Does this fit the definition of weath

Rus_ich [418]

Answer:

what is your age po? what

8 0

3 years ago

What is (Fnet3)x, the x-component of the net force exerted by these two charges on a third charge q3

Pachacha [2.7K]

This question is incomplete, the complete question is;

Coulomb's law for the magnitude of the force F between two particles with charges Q and Q' separated by a distance d is

|FI = |QQ'I / d²

where K = 1/4π∈0, and

∈0 = 8.854 × 10⁻¹² C²/(N.m²) is the permittivity of free space.

Consider two point charges located on the x-axis:

one charge, q₁ = -18.5 nC, is located at

x₁ = -1.715m; the charge q₂ = 30.5 nC, is at the origin ( x₂=0 )

What is (Fnet3)x, the x-component of the net force exerted by these two charges on a third charge q₃ = 51.0 nC placed between q₁ and q₂ at x₃ = -1.085 m ?

Answer: (Fnet3)x = -3.3287 × 10⁻⁵ N

Explanation:

Given that;

Q₁ = -18.5 nC Q₃ = 51 nC Q₂ = 30.5 nC

x₁ = - 1.715m x₃ = - 1.085m x₂ = 0

Now

x - component of Net force on charge Q₃ is

(Fnet3)x = -K|Q₁I|Q₃I / r₁3² - -K|Q₂I|Q₃I / r₂3²

(Fnet3)x = -(9×10⁹)(51×10⁻⁹) [ 18.5 / ((-1.085 + 1.715)²) + (30.5 / (-1.085)² ] × 10⁻⁹

(Fnet3)x = -3.3287 × 10⁻⁵ N

6 0

3 years ago

Deduce the dimension of Impulse

lawyer [7]

Answer:

The impulse is dimensionally represented as [M1 L1 T-1].

or,

Impulse = Force × (final time – initial time) Impulse = Force × \Delta t. I = F × \Delta t.

7 0

3 years ago

Captain Jack Sparrow has been marooned on an island in the Atlantic by his crew, and decides to builda raft to escape. The wind

Marianna [84]

Answer:

d₃ = 37,729 km, θ= 5.1º North of West

Explanation:

This is a velocity addition problem, the easiest way to solve it is to decompose the velocities in a Cartesian system, the x-axis coincides with the West-East direction and the y-axis with the South-North direction

* first displacement is

d₁ₓ = 11 km

* second offset is

cos 6 = d₂ₓ / d₂

sin 6 = d_{2y} / d₂

d₂ₓ = d₂ cos 6

d_{2y} = d₂ sin 6

d₂ₓ = 6 cos 6 = 5.967 km

d_{2y} = 6 sin 6 = 0.6272 km

* third displacement is unknown

* fourth and last displacement

cos (-11) = d₄ₓ / d₄

sin (-11) = d_{4y} / d₄

d₄ₓ = d₄ cos (-11)

d_{4y} = d₄ sin (-11)

d₄ₓ = 21 cos (-11) = 20.61 km

d_{4y} = 21 sin (-11) = -4.007 km

They tell us that at the end of the tour you are back on the island, so the displacement must be zero

X axis

x = d₁ₓ + d₂ₓ + d₃ₓ + d₄ₓ

0 = 11 +5.967 + d₃ₓ + 20.61

d₃ₓ = -11 - 5.967 - 20.61

d₃ₓ = -37.577 km

Y axis

y = d_{1y} + d_{2y} + d_{3y} + d_{4y}

0 = 0 + 0.6272 + d_{3y} -4.007

d_{3y} = 4.007 - 0.6272

d_{3y} = 3.3798 km

This distance can be given in the form of module and angle

Let's use the Pythagorean theorem for the module

d₃ = $\sqrt{d_{3x}^2 + d_{3y}^2}$

d₃ = $\sqrt{37.577^2 + 3.3798^2}$

d₃ = 37,729 km

Let's use trigonometry for the angle

tan θ = d_{3y} / d₃ₓ

θ = tan⁻¹ $\frac{d_{3y}}{d_{3x}}$

θ = tan-1 (-3.3798 / 37.577)

θ = 5.1º

Since the y coordinate is positive and the x coordinate is negative, this angle is in the second quadrant, so the direction given in the form of cardinal coordinates is

θ= 5.1º North of West

3 0

3 years ago

A slanted surface used to raise an object is a(n)​

A slanted surface used to raise an object is a(n)