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3 years ago

Simplify the expression insert √96/8

Mathematics

2 answers:

Sever21 [200]3 years ago

6 0

The answer is 2√3
I hope this answers your question :)

kati45 [8]3 years ago

3 0

First simplify the inside of the squareroot.

96/8=12

You cannot solve for the squareroot of 12, so find factors of 12 that can be squarerooted.

4(3)=12 and 4 can be square-rooted.

The squareroot of 4 is 2, and the squareroot of 3 is irrational.

The answer is 2√3

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A watering can contained 512 quarts water. After all the plants were watered, only 4 cups remained. How many cups of water were

Sedaia [141]

Answer:

2044 cups

Step-by-step explanation:

number of cups left = number of cups in the watering can - number of cups remaining

convert the capacity of the watering can to cups

1 quart = 4 cups

512 x 4 = 2048

2048 - 4 = 2044

8 0

3 years ago

What number nearest to 100,000 is exactly divisible by 2, 3, 4, 5, 6 and 7?

navik [9.2K]

First find the numbers with the factors of:
2,3,4,5,6,7
find the minum
if something has a factor of 6 then it also has a factor of 3 and 2 so just multiply by the lcm of all of them which is found by
2=2
3=3
4=2 times 2
5=5
6=2 times 3
7=7

LCM=2 times 2 times 3 times 5 times 7=420

now divide 100000 by 420 and round down
100000/420=238.095=238.1 round doen 238

multiply 420 by 238 and get 99960

that is the answer 99960

4 0

3 years ago

Find a polynomial with integer coefficients that satisfies the given conditions. R has degree 4 and zeros 3 − 3i and 2, with 2 a

dolphi86 [110]

Answer:

The required polynomial is $P(x)=x^4-10x^3+46x^2-96x+72$ .

Step-by-step explanation:

If a polynomial has degree n and $c_1,c_2,...,c_n$ are zeroes of the polynomial, then the polynomial is defined as

$P(x)=a(x-c_1)(x-c_2)...(x-x_n)$

It is given that the polynomial R has degree 4 and zeros 3 − 3i and 2. The multiplicity of zero 2 is 2.

According to complex conjugate theorem, if a+ib is zero of a polynomial, then its conjugate a-ib is also a zero of that polynomial.

Since 3-3i is zero, therefore 3+3i is also a zero.

Total zeroes of the polynomial are 4, i.e., 3-3i, 3_3i, 2,2. Let a=1, So, the required polynomial is

$R(x)=(x-3+3i)(x-3-3i)(x-2)(x-2)$

$R(x)=((x-3)+3i)((x-3)-3i)(x-2)^2$

$R(x)=(x-3)^2-(3i)^2((x-3)-3i)(x-2)^2$ $[a^2-b^2=(a-b)(a+b)]$

$R(x)=(x^2-6x+9-9(i)^2((x-3)-3i)(x-2)^2$

$R(x)=(x^2-6x+18)(x^2-4x+4)$ $[i^2=-1]$

$R(x)=(x^2-6x+18)(x^2-4x+4)$

$R(x)=x^4-10x^3+46x^2-96x+72$

Therefore the required polynomial is $P(x)=x^4-10x^3+46x^2-96x+72$ .

3 0

3 years ago

Can someone please help me with this ❤️❤️

kherson [118]

Answer:

See below for answers

Step-by-step explanation:

y=5(2)ˣ

y=5(2)⁻²=5(1/2²)=5(1/4)=5/4

y=5(2)⁻¹=5(1/2¹)=5(1/2)=5/2

y=5(2)⁰=5(1)=5

y=5(2)¹=5(2)=10

y=5(2)²=5(4)=20

8 0

3 years ago

In file, please answer with prooooooof :D

BigorU [14]

Answer:

B. 128 square centimeters

Step-by-step explanation:

So first make the top triangle part its own figure. By using information provided you can figure out the height of the triangle would be 3 by subtracting 11 from 14. Take 3 multiply it by the base and then 1/2 to get 18. Then find the area of the rectangle which would be 10 times 11 which is 110. Add the areas of the two parts, 110 and 18 to get 128.

6 0

4 years ago