A.) y = ut - 1/2gt^2 + 12
y = 6t - 1/2(9.8)t^2 + 12
y = 6t - 4.9t^2 + 12
b.) The y-intercept is 12
c.) The y-intercept represent the height of the ball at time t = 0
d.) At the time the ball reaches the ground, y = 0
-4.9t^2 + 6t + 12 = 0
t = 2.29 seconds
Therefore, it took the ball 2.29 seconds to reach the ground.
Hi I think it is 83,023,007
Answer:
f(x)=8*(3.5)^x
Step-by-step explanation:
2=98
3= 98r
4= 98r^2
5= 98r^3
6= 98r^4
98r^4/98, 98 crosses out and its just r^4. r^4= 14706.125/98
r=3.5
So you plug that in and you get f(x)=8*(3.5)^x
I hope this helped. XD
Answer:
2x^2-2x+9
Step-by-step explanation:
Angle A is smallest
Then angle B
And angle C is largest
Should be correct... it may vary depending on where A, B, and C are located on the triangle
