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2 years ago

What does the chemical formula C3H6O2 tell about a molecule of the compound it represents?

Chemistry

2 answers:

NARA [144]2 years ago

9 0

Answer: The correct option is C.

Explanation: For a given chemical formula $C_3H_6O_2$

3 different elements are present in this molecule that are Carbon, Hydrogen and Oxygen.

Number of Carbon atoms present = 3

Number of Hydrogen atoms = 6

Number of oxygen atoms = 2

Total number of atoms in the given molecule = 3 + 6 + 2 = 11

Hence, This molecule is made up of total 11 atoms of 3 different elements. Therefore, the correct option is C.

finlep [7]2 years ago

5 0

I think it might be C

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Chromium(III) oxide can be prepared by heating chromium(IV) oxide in vacuo at high temperature: 4Cr02 —2Cr2O3 +02 The reaction o

kkurt [141]

<u>Answer:</u> The theoretical yield and percent yield of chromium (III) oxide is 434.72 grams and 92.6 % respectively.

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ .....(1)

Given mass of $CrO_2$ = 480.1 g

Molar mass of $CrO_2$ = 84 g/mol

Putting values in equation 1, we get:

$\text{Moles of }CrO_2=\frac{480.1g}{84g/mol}=5.72mol$

For the given chemical equation:

$4CrO_2\rightarrow 2Cr_2O_3+O_2$

By Stoichiometry of the reaction:

4 moles of $CrO_2$ produces 2 moles of chromium (III) oxide

So, 5.72 moles of $CrO_2$ will produce = $\frac{2}{4}\times 5.72=2.86mol$ of chromium (III) oxide

Now, calculating the mass of chromium (III) oxide from equation 1, we get:

Molar mass of chromium (III) oxide = 152 g/mol

Moles of chromium (III) oxide = 2.86 moles

Putting values in equation 1, we get:

$2.86mol=\frac{\text{Mass of chromium (III) oxide}}{152g/mol}\\\\\text{Mass of chromium (III) oxide}=(2.86mol\times 152g/mol)=434.72g$

To calculate the percentage yield of chromium (III) oxide, we use the equation:

$\%\text{ yield}=\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100$

Experimental yield of chromium (III) oxide = 402.4 g

Theoretical yield of chromium (III) oxide = 434.72 g

Putting values in above equation, we get:

$\%\text{ yield of chromium (III) oxide}=\frac{402.4g}{434.72g}\times 100\\\\\% \text{yield of chromium (III) oxide}=\%$

Hence, the theoretical yield and percent yield of chromium (III) oxide is 434.72 grams and 92.6 % respectively.

7 0

2 years ago

Please help. Thank you:)

bearhunter [10]

These are guesses because there is no word bank or anything

A. Water
B. Housing
C. Plants
D. Animals
E. Warmth

5 0

2 years ago

Which element probably reacts most like bromine, Br?

Nikitich [7]

D) Chlorine, Cl. Hope that helped

8 0

2 years ago

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Murrr4er [49]

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2 years ago

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How many grams of water are theoretically produced for the following reaction given we have 2.6 moles of HCl and 1.4 moles of Ca

leva [86]

Answer:

The answer to your question is: 6.8 g of water

Explanation:

Data

2.6 moles of HCl

1.4 moles of Ca(OH)2

2HCl + Ca(OH)2 → 2H2O + CaCl2

MW 2(36.5) 74 36 g 111 g

73g

1 mol of HCl ---------------- 36.5 g

2.6 mol -------------- x

x = (2.6 x 36.5) / 1 = 94.9 g

1 mol of Ca(OH)2 -------------- 74 g

1.4 mol --------------- x

x = (1.4 x 74) / 1 = 103.6 g

Grams of water

73 g of HCl ------------------ 36g of H2O

94.9 g ------------------- x

x = (94.9 x 36) / 73 = 46.8 g of water

6 0

2 years ago