Number of moles in mercury oxide = 0.00981 moles ![O_{2}](https://tex.z-dn.net/?f=O_%7B2%7D)
Number of oxide required in decomposition of mercury = 4.249 g ![H_{g} O](https://tex.z-dn.net/?f=H_%7Bg%7D%20O)
Percentage of mercury required = 87.6%
Evaluating the value :
First determine the number of moles of
obtained using the ideal gas law.
To use the gas constant 0.0821 L-atm/mole-degree, the pressure and volume must be changed to atmospheres and liters and the temperature changed to degrees K.
To find the number of moles use
n =
= 735/760 x 0.254 / 0.082 x 305.15
= 0.00981 moles.![O_{2}](https://tex.z-dn.net/?f=O_%7B2%7D)
The balanced equation is 2
====> 2Hg + ![O_{2}](https://tex.z-dn.net/?f=O_%7B2%7D)
so a conversion factor to get grams
from moles
is
2 x 216.59 g HgO / 1 mole
= 433.18.
The grams of HgO then is 433.18 x 0.00981
= 4.249 g HgO required to produce 0.00981 moles of O2 by decomposition.
The percent of HgO in the mixture is then
= 4.249 / 4.85 x 100
= 87.6%.
Mixture of mercury :
The element mercury is a pure substance. Nickel sulfate is also a pure substance but it is a compound of the elements nickel, sulfur, and oxygen.
Mercury is a compound that can be found naturally in the environment. It can be found in metal form, as mercury salts or as organic mercury compounds.
Learn more about mercury compound :
brainly.com/question/1711938
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