1/2 dozen pencils in 1/3 box
what about 1 dozen
we cross miltiply this to get
1/3*2=2/3
doing the same for all the questions we get
1/4*5/4=5/20
3/4*5/3=15/12
3/10*12/7=18/35
Answer:
Step-by-step explanation: true
Answer:
He won 13 times and lost 1 time
Step-by-step explanation:
divide 67 by 5 so 67÷5 you would get 13.4 you take the whole number 13 and multiply it by 5 and that will get you to 65 so then you only have 2 left over and if you lose you get 2 point so therefore you know that he lost only once
(13•5)+2=67
Answer: The required probability is 0.414.
Step-by-step explanation:
Since we have given that
Probability of taxis in a certain city by Blue Cab P(B)= 15%
Probability of taxis by Green Cab P(G) = 85%
Let A be the event that eyewitness said that vehicle was blue.
P(A|B)=0.80
P(A|G)=0.80
P(A'|B)=0.20=P(A'|G)
Using the "Bayes theorem":
Probability that the taxi at fault was blue is given by

Hence, the required probability is 0.414.
Answer:
By long division (x³ + 7·x² + 12·x + 6) ÷ (x + 1) gives the expression;

Step-by-step explanation:
The polynomial that is to be divided by long division is x³ + 7·x² + 12·x + 6
The polynomial that divides the given polynomial is x + 1
Therefore, we have;

(x³ + 7·x² + 12·x + 6) ÷ (x + 1) = x² + 5·x + 7 Remainder -1
Expressing the result in the form
, we have;