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2 years ago

PLease help I don't know what I'm doing here

Mathematics

1 answer:

Dvinal [7]2 years ago

3 0

Step-by-step explanation:

y = 28 - 2x

x = 1, y = 28 - 2(1) = 26

x = 3, y = 28 - 2(3) = 22

x = 4, y = 28 - 2(4) = 20

x = 5, y = 28 - 2(5) = 18

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Can someone plz help me with this one problem plz

ICE Princess25 [194]

8mm bc a=lw. If a=32 and l=4, you get 4w=32. Then, solve for w.

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2 years ago

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If ∠A and ∠B are supplementary and m∠A = 37°45', then m∠B = ______.

xenn [34]

Answer: 142°15'

Explanation:

Supplementary angles are angles that add up to make a straight angle ( $180^{\circ}$ ).

Therefore, we must find the angle ∠B such that

∠A + ∠B = 180° (1)

We know that ∠A = 37°45', so we can re-arrange equation (1) to find the magnitude of ∠B:

∠B = 180° - ∠A = 180° - 37°45' = 142°15'

So, the correct answer is

142°15'

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3 years ago

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Determine side x. Round to the nearest unit. 20 9 12 5

tatyana61 [14]

Answer:

Step-by-step explanation:

First, you will have to use trigonometry. Since the side of the triangleis the opposite of the angle 53 and the hypotenuse, you will use sin.

Sin 53 degrees = opposite side / hypotenuse side.

The opposite side is x and the hypotenuse side equals 15.

sin53= x/15

15 ( sin 53 ) =x

x= 11.97953

Round

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2 years ago

What is the value of x in the equation (-35)X = 1? Explain.

Ipatiy [6.2K]

Answer:

x= - 1/35. I'm pretty sure this is right.

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2 years ago

From a radar station, the angle of elevation of an approaching airplane is 32.5 degree. The horizontal distance between the plan

denis23 [38]

Answer: 42.21 km

Step-by-step explanation:

We can solve this using trigonometry, since we have the following data:

$\theta=32.5\°$ is the the angle of elevation

$d=35.6 km$ is the horizontal distance between the plane and the radar station

$x$ is the hypotenuse of the right triangle formed between the radar station and the airplane

Now, the trigonometric function that will be used is <u>cosine</u>:

$cos\theta=\frac{d}{x}$ because $d$ is the adjacent side of the right triangle

$cos(32.5\°)=\frac{35.6 km}{x}$

Finding $x$ :

$x=\frac{35.6 km}{cos(32.5\°)}$

$x=42.21 km$

4 0

3 years ago