Find the equation of a line that is parallel to y = 2x + 3 and passes through (-1, -1).

Mathematics

1 answer:

drek231 [11]4 years ago

4 0

Answer:

y = 2x +1

Step-by-step explanation:

The given line is in "slope-intercept" form, where the slope is the coefficient of x, 2, and the intercept is the added constant, 3. The parallel line will have the same slope, but its constant will be different. We can find the constant by putting the given point into an equation with the constant as the unknown:

y = 2x + b

-1 = 2(-1) +b . . . substitute for x and y

2 -1 = b . . . . . . add 2

1 = b

So the equation for the parallel line is ...

y = 2x + 1

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