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MA_775_DIABLO [31]

2 years ago

10

Please answer this question

1 answer:

Semmy [17]2 years ago

4 0

Answer: -3x + 15

Step-by-step explanation: you multiply -3 by x so you get -3x, then you multiply -3 by -5 and get +15, then you just put the two together in an equation.

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Bond [772]

D. The elevator takes 37.5 seconds to move down to the lobby.

8x+y=300

y= 300-8x
y= 300 - 8 (37.5)

y = 300-300
y = 0

wheb y =0 that means that the height is 0

5 0

3 years ago

Plz help <br> What does “|” mean in mathematical term <br> Thanks

vova2212 [387]

Answer:

Step-by-step explanation:

If you meant " | ", as in |x|, that's "absolute value." The domain of this function is "all real numbers," and the range is "all real numbers zero or greater."

8 0

3 years ago

The ratio of blue jays to Robin's was 6 to 7. If there were 84 Robins, how many blue jays were there?

Paul [167]

Answer:

72

Step-by-step explanation:

<em>Since the ratio of blue jays to robin's was 6 to 7 then if there were 84 robins how many blue jays were there.</em>

<em>6 to 7 can also be express as 6/7</em>

<em>Thus, we can set up a proportion</em>

<em>6/7 = x/84</em>

<em>Now, we have to solve for x</em>

<em>x = 72</em>

<em>Hence, if there were 84 robin there would be 72 blue jays.</em>

<em />

<u><em>~lenvy~</em></u>

3 0

2 years ago

Find the angle between the given vectors. Round your answer, in degrees, to two decimal places. u=⟨2,−6⟩u=⟨2,−6⟩, v=⟨4,−7⟩

NISA [10]

Answer:

$\theta = 108.29$

Step-by-step explanation:

Given

$u =$

$v =$

Required:

Calculate the angle between u and v

The angle $\theta$ is calculated as thus:

$cos\theta = \frac{u.v}{|u|.|v|}$

For a vector

$A =$

$A = a * b$

$cos\theta = \frac{u.v}{|u|.|v|}$ becomes

$cos\theta = \frac{.}{|u|.|v|}$

$cos\theta = \frac{2*6+4*-7}{|u|.|v|}$

$cos\theta = \frac{12-28}{|u|.|v|}$

$cos\theta = \frac{-16}{|u|.|v|}$

For a vector

$A =$

$|A| = \sqrt{a^2 + b^2}$

So;

$|u| = \sqrt{2^2 + 6^2}$

$|u| = \sqrt{4 + 36}$

$|u| = \sqrt{40}$

$|v| = \sqrt{4^2+(-7)^2}$

$|v| = \sqrt{16+49}$

$|v| = \sqrt{65}$

So:

$cos\theta = \frac{-16}{|u|.|v|}$

$cos\theta = \frac{-16}{\sqrt{40}*\sqrt{65}}$

$cos\theta = \frac{-16}{\sqrt{2600}}$

$cos\theta = \frac{-16}{\sqrt{100*26}}$

$cos\theta = \frac{-16}{10\sqrt{26}}$

$cos\theta = \frac{-8}{5\sqrt{26}}$

Take arccos of both sides

$\theta = cos^{-1}(\frac{-8}{5\sqrt{26}})$

$\theta = cos^{-1}(\frac{-8}{5 * 5.0990})$

$\theta = cos^{-1}(\frac{-8}{25.495})$

$\theta = cos^{-1}(-0.31378701706)$

$\theta = 108.288386087$

<em></em> $\theta = 108.29$ <em> (approximated)</em>

4 0

2 years ago

A line intersects the point (6,9) and (7,4). What is the slope intercept equation for this line?

BartSMP [9]

Answer:

im kind of rusty on this math but i think the equation would be y=-5x+b i forgot how to find b tho :( im sorry

6 0

3 years ago