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natita [175]
3 years ago
15

there are 6 girls and 7 boys in a class. a team of 10 players is to be selected from each class. how many different combinations

of players are possible?
Mathematics
1 answer:
galben [10]3 years ago
5 0

Answer:

Answer: 286

Step-by-step explanation:

6+7=13

13C10=286  

Answer: 286

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At a sale this week, a desk is being sold for $336. This is a 36% discount from the original price.
8090 [49]

Answer:

$525

Step-by-step explanation:

We can find the original price by using the formula x - 0.36x = 336, where x is the original price, 0.36 is the discount percentage (converted to decimal form), and 336 is the total amount paid after the discount is applied:

x-0.36x=336\\0.64x=336\\x=525

To check and further understand why the formula works, we can simply apply the discount to the original price and subtract the number from the original price:

525 * 0.36 = 189

525 - 189 = 336

Modeling the first formula gives us:

525 - (0.36 * 525) = 336

525 - 189 = 336

6 0
1 year ago
THIS IS URGENTE I AM BEING TIMED PLZ HELP, if you answer both correct i will mark you brainlyist
Lapatulllka [165]
Area would be 4.52 A= pi x radius squared
Circumference would be 7.54 C= 2 pi radius. Hope that makes sense.
4 0
3 years ago
Your monthly bill went frm 57.98 to 62.49 whats the percent change
nekit [7.7K]
D is your answer for your question
6 0
3 years ago
Who invented crayons
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Alice Binney invented them.
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3 years ago
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Find Dy/dX when x^y×y^x=1​
victus00 [196]

by dy/dx, we'll be assuming that "y" is encapsulating a function, a function in terms of "x".

x^y\cdot y^x=1\implies \stackrel{\textit{\large product rule}}{\stackrel{\textit{chain rule}}{yx^{y-1}(1)}\cdot y^x+x^y\cdot \stackrel{\textit{chain rule}}{xy^{x-1}\cdot \frac{dy}{dx}}}~~ = ~~0 \\\\\\ y^{1+x}x^{y-1}+x^{y+1}y^{x-1}\cdot \cfrac{dy}{dx}=0\implies \cfrac{dy}{dx}=\cfrac{-y^{1+x}x^{y-1}}{x^{y+1}y^{x-1}} \\\\\\ \cfrac{dy}{dx}=-~~ y^{(1+x)-(x-1)}~~x^{(y-1)-(y+1)} \\\\\\ \cfrac{dy}{dx}=-~~ y^2x^{-2}\implies \cfrac{dy}{dx}=\cfrac{-y^2}{x^2}

7 0
2 years ago
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