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kykrilka [37]
3 years ago
10

1.-( -1/5) + ( -3/5) =

Mathematics
1 answer:
m_a_m_a [10]3 years ago
7 0

Answer:

here

Step-by-step explanation:

1.-( -1/5) + ( -3/5) = - 4/5

2.- (+2/6) + (-5/6)= - 1/2

3.-(-4/12) + (-4/6)- (- 1/3)= - 2/3

4.- (- 5/12) + (+4/20)= - 16/30

5.- (-6/12) + (-1/6) = - 4/6

1.- (+8) + (-12)= -4

2.- (-3) + ( -9 )= -12

3.- (-2) + (-15) = -17

4.- (-5) – ( +10 )= -15

5.- (+7) – ( - 8) = 15

1.- (-1/5) + (-3/5)= - 4/5

2.- (+2/6) + (-5/6)= - 1/2

3.-(-9/12) + (-1/6)= - 11/12

4.- (+1/3) + (+4/6) +(-1/3)= 2/3

5.- (-1/4) + (+4/2) – (- ¼)= 2

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Given that f(x) = x2 – 3x - 10 and g(x) = x – 5, find (f - g)(x) and express
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Answer:

(f-g)(x)= x^2-4x-5

Step-by-step explanation:

We have the two functions:

f(x)=x^2-3x-10\text{ and } g(x)=x-5

And we want to find (f-g)(x).

(f-g)(x) is equivalent to f(x)-g(x).

Therefore:

\begin{aligned} (f-g)(x)&=f(x)-g(x)\\ &=(x^2-3x-10)-(x-5)\end{aligned}

Simplify:

\begin{aligned} &=x^2-3x-10-x+5 \\ &=(x^2)+(-3x-x)+(-10+5) \\ &=x^2-4x-5\end{aligned}

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(f-g)(x)= x^2-4x-5

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