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3 years ago

1.-( -1/5) + ( -3/5) =

Mathematics

1 answer:

m_a_m_a [10]3 years ago

7 0

Answer:

here

Step-by-step explanation:

1.-( -1/5) + ( -3/5) = - 4/5

2.- (+2/6) + (-5/6)= - 1/2

3.-(-4/12) + (-4/6)- (- 1/3)= - 2/3

4.- (- 5/12) + (+4/20)= - 16/30

5.- (-6/12) + (-1/6) = - 4/6

1.- (+8) + (-12)= -4

2.- (-3) + ( -9 )= -12

3.- (-2) + (-15) = -17

4.- (-5) – ( +10 )= -15

5.- (+7) – ( - 8) = 15

1.- (-1/5) + (-3/5)= - 4/5

2.- (+2/6) + (-5/6)= - 1/2

3.-(-9/12) + (-1/6)= - 11/12

4.- (+1/3) + (+4/6) +(-1/3)= 2/3

5.- (-1/4) + (+4/2) – (- ¼)= 2

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The sum of three numbers is 11 . The sum of twice the first number, 5 times the second number, and 6 times the third number is

Assoli18 [71]

Answer:

4, 6, 1

Step-by-step explanation:

We can solve this problem using a system of equations:

1) a + b + c = 11

2) 2a + 5b + 6c = 44

3) 4a - b = 10

First, we can substitute the value of b from equation #3 into equation #1:

b = 4a - 10

a + (4a - 10) + c = 11

5a - 10 + c = 11

5a + c = 21

c = 21 - 5a

Now, we can plug the values of b and c into equation #2, as b and c are represented in terms of a:

2a + 5(4a - 10) + 6(21 - 5a) = 44

2a + 20a - 50 + 126 - 30a = 44

-8a + 76 = 44

-8a = -32

a = 4

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2 years ago

Solve for x! Please help!

erica [24]

Answer:

Step-by-step explanation:

ΔADC and ΔCDB are similar (AA). Therefore the sides are in proportion:

$\dfrac{AD}{DC}=\dfrac{DC}{DB}$

We have AD = 16, DC = x, DB = 9. Substitute:

$\dfrac{16}{x}=\dfrac{x}{9}$ <em>cross multiply</em>

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3 years ago