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2 years ago

Worth a lot of points

Mathematics

1 answer:

Dima020 [189]2 years ago

3 0

6. Is 6MPH because 12M / 2H
8. Is 40Seconds because 120 / 3
10. Is 113.3 seconds

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The circumference of a circle is 11 pi ft. find its diameter, in feet

nexus9112 [7]

Answer:

11 feet

Step-by-step explanation:

Use the circumference formula, C = $\pi$ d

Plug in 11 $\pi$ as C, and solve for d:

C = $\pi$ d

11 $\pi$ = $\pi$ d

11 = d

So, the diameter is 11 feet

7 0

3 years ago

By what number should-15/56 be divided to get -5/6 pls pls pls pls I need your help

mr_godi [17]

Answer:

The desired divisor is n = 21

Step-by-step explanation:

Let that number be n. Then:

-15/56 -5

---------- = ---------

n 6

Through cross-multiplication we get:

(-15/56)*6 = -5n, which reduces to:

(-15)(7) = -5n, or 3(7) = n

The desired divisor is n = 21

6 0

2 years ago

Memory module consists of 9 chips. The device is designed with redundancy so that it works even if one of its chips is defective

soldier1979 [14.2K]

Answer:

a) $P[C]=p^n$

b) $P[M]=p^{8n}(9-8p^n)$

c) n=62

d) n=138

Step-by-step explanation:

Note: "Each chip contains n transistors"

a) A chip needs all n transistor working to function correctly. If p is the probability that a transistor is working ok, then:

$P[C]=p^n$

b) The memory module works with when even one of the chips is defective. It means it works either if 8 chips or 9 chips are ok. The probability of the chips failing is independent of each other.

We can calculate this as a binomial distribution problem, with n=9 and k≥8:

$P[M]=P[C_9]+P[C_8]\\\\P[M]=\binom{9}{9}P[C]^9(1-P[C])^0+\binom{9}{8}P[C]^8(1-P[C])^1\\\\P[M]=P[C]^9+9P[C]^8(1-P[C])\\\\P[M]=p^{9n}+9p^{8n}(1-p^n)\\\\P[M]=p^{8n}(p^{n}+9(1-p^n))\\\\P[M]=p^{8n}(9-8p^n)$

$P[M]=(0.999)^{8n}(9-8(0.999)^n)=0.9$

This equation was solved graphically and the result is that the maximum number of chips to have a reliability of the memory module equal or bigger than 0.9 is 62 transistors per chip. See picture attached.

d) If the memoty module tolerates 2 defective chips:

$P[M]=P[C_9]+P[C_8]+P[C_7]\\\\P[M]=\binom{9}{9}P[C]^9(1-P[C])^0+\binom{9}{8}P[C]^8(1-P[C])^1+\binom{9}{7}P[C]^7(1-P[C])^2\\\\P[M]=P[C]^9+9P[C]^8(1-P[C])+36P[C]^7(1-P[C])^2\\\\P[M]=p^{9n}+9p^{8n}(1-p^n)+36p^{7n}(1-p^n)^2$

We again calculate numerically and graphically and determine that the maximum number of transistor per chip in this conditions is n=138. See graph attached.