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3 years ago

The equations to this problem .

Mathematics

2 answers:

Annette [7]3 years ago

8 0

Answer:

The answer would be the third one.

Lina20 [59]3 years ago

8 0

the answer to this problem is y=11/4

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(y + 4 / 2y) + (y-2 / 3) = (3y^2 + 10 / 6y) for y<br>{-2, 1}<br>{-2, 3}<br>{}

vaieri [72.5K]

Answer:

{-2, 1}

Step-by-step explanation:

$\frac{y+4}{2y} +\frac{y-2}{3} =\frac{3y^2+10}{6y}$

Make the fractions have a common denominator.

$\frac{3}{3} (\frac{y+4}{2y}) +\frac{x}{y} (\frac{y-2}{3}) =\frac{3y^2+10}{6y}\\\frac{3y+12}{6y} +\frac{2y^2-4y}{6y} =\frac{3y^2+10}{6y}\\\frac{2y^2-y+12}{6y} =\frac{3y^2+10}{6y}$

Now that both sides of the equation have a common denominator, you can cancel out the denominators.

$2y^2-y+12=3y^2+10$

Now, set the equation equal to zero and factor.

$2y^2-y+12=3y^2+10\\-y^2-y+2=0\\(-y-2)(y-1)=0\\\\-y-2=0\\y=2\\\\y-1=0\\y=-1$

The y-values are {-2, 1}

6 0

3 years ago

What does the line in a scatter plot mean?

irakobra [83]

Answer:

the line represents the average slope in which the dots line up. in other words, it shows where most of the options/solutions are on the plot

Step-by-step explanation:

nice pfp

6 0

2 years ago

Given cos theta = - 2/5 and sin theta < 0, find the six trigonometric values. I need help with this

Lena [83]

Answer:

$\sin\,\theta =-\frac{\sqrt{21} }{5}$

$\tan\,\theta =\frac{\sqrt{21} }{2}$

$\sec\,\theta = \frac{-5}{2}$

$cosec\,\theta =\frac{-5}{\sqrt{21} }$

$\cot\,\theta =\frac{2}{\sqrt{21} }$

Step-by-step explanation:

$\cos\theta =\frac{-2}{5}$

As both $sin\,\theta$ ,

$\theta$ lies in the third quadrant.

In the third quadrant,

$\sin\theta$

$\sin\,\theta =-\sqrt{1-\cos^2\,\theta} \\=-\sqrt{1-(\frac{-2}{5})^2 } \\\\=-\sqrt{1-\frac{4}{25} }\\\\=-\sqrt{\frac{25-4}{25} }\\\\=-\frac{\sqrt{21} }{5}$

$\tan\,\theta = \frac{\sin\,\theta}{\cos\,\theta }\\\\=\frac{\frac{-\sqrt{21} }{5} }{\frac{-2}{5} }\\\\=\frac{\sqrt{21} }{2}$

$\sec\,\theta =\frac{1}{\cos\,\theta }\\\\=\frac{1}{\frac{-2}{5} }\\\\=\frac{-5}{2}$

$\ cosec \,\theta = \frac{1}{sin\,\theta }\\\\=\frac{1}{\frac{-\sqrt{21} }{5} }\\\\=\frac{-5}{\sqrt{21} }$

$\cot\,\theta =\frac{1}{\tan\,\theta}\\\\=\frac{1}{\frac{\sqrt{21} }{2} }\\\\=\frac{2}{\sqrt{21} }$

3 0

3 years ago

In rectangle ABCD, AB = 10 cm and BC = 14 cm. If rectangle EFGH is the image after a dilation, which could be its side lengths?

lana [24]

Answer is D

After dilation the image remain same but it is stretched or shrinked to the original size.

That means the ratio of the sides and the angles between the sides remain same .

Here we did dilation of ABCD which made it to EFGH.

Hence the ratio of the corresponding sides of the original rectangle ABCD should remain same even after dilation.

the corresponding sides are : AB and EF

BC and FG

CD and GH

DA and HE

* Let us find ratio of the sides AB and BC

given that AB= 10 and BC= 14

AB/BC= 10/14 = 5 /7 ( 10 and 14 both are multiple of 2 so we reduced them by a factor of 2 )

* the raio of the corresponding sides EF and FG should be same ( 5/7)

in the option D EF= 25 and FG= 35

so EF/FG= 25/35 = 5 /7 ( both are multiple of 5 so we reduced them by the factor of 5 )

Since ratio of the corresponding sides are coming out to be same for the EFGH given in option D it should be the dilation of the ABCD

4 0

3 years ago

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USPS charges a flate rate of $5.50 for the 1st pound of shipping, plus $1.35 for each additional pound. FedEx charges $8.00 for

Rasek [7]

usps is cheaper

Step-by-step explanation:

usps equals 6 dollars 85 cents and fedex charges 9 dollars and 10 cents

5 0

3 years ago

Read 2 more answers