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luda_lava [24]
3 years ago
10

The equations to this problem .

Mathematics
2 answers:
Annette [7]3 years ago
8 0

Answer:

The answer would be the third one.

Lina20 [59]3 years ago
8 0
the answer to this problem is y=11/4
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Simplify: square root 27x12 over 300x8
alex41 [277]

Answer:

10

-------------

3x^2

Step-by-step explanation:

First lets simplify what is inside the square root

300x8

---------------

27x12

3 * 100 x^8

------------------

3 *9 x^12

The 3's cancel  and we know a^b/ a^c = a^(b-c)

100/9 x^ (8-12)

100/9 x^-4

sqrt( 100/9 x^-4)

Put the negative exponent in the denominator and make it positive

sqrt( 100 / (9x^4) )

We know that sqrt( a / b) = sqrt(a) / sqrt( b)

sqrt(100)

----------------

sqrt( 9x^4)

10

-------------

3x^2

Read more on Brainly.com - brainly.com/question/12900964#readmore

5 0
4 years ago
Does 4/8 +7/8=11/16 or 11/8
ss7ja [257]
That's easy it is 11/8 because 4+7=11 8 will be the same
5 0
3 years ago
Read 2 more answers
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uysha [10]
Y axis and quadrant IV
6 0
3 years ago
A ribbon is cut into n parts. The length of each part increases such that they form a geometric progression. SPM Given the lengt
emmainna [20.7K]

Answer:

Step-by-step explanation:

Let\ say\ r \ the \common\ ratio:\\a)a_4=r^2*a_2=9*a_2\Longrightarrow\ r=3\ (not\ -3\ since\ parts\ are\ positive)\\\\b)\\\displaystyle \sum_{i=1}^{n} a_i =a_1+a_2+a_3+...+a_n\\\\=a_1+a_1*r+a_1*r^2+a_1*r^3+...+a_1*r^{n-1}\\\\=a_1*(1+r+r^2+...+r^{n-1})\\\\=a_1*\dfrac{r^n-1}{r-1} \\\\147620=5*\frac{(3^n-1)}{3-1} \\\\3^n-1=\frac{2*147620}{5} \\\\3^n=59049 \\\\n*ln(3)=ln(59049)\\\\n=\dfrac{ln(59049)}{ln(3)} \\\\n=10\\\\a_n=5*3^{10-1}=5*19683=98415(cm)

5 0
3 years ago
Seven less than three times a number is two.
Stells [14]

Answer:

let x be the number

seven less than three times a number ==> 3x - 7

Step-by-step explanation:

6 0
3 years ago
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