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alina1380 [7]
3 years ago
8

An ideal gas is held in a rigid container at temperature of 201∘C. Upon cooling the gas, the pressure decreases by a factor of 2

.0, while the volume and the amount of gas remain constant. What must be the final temperature of the gas?
Chemistry
1 answer:
miskamm [114]3 years ago
3 0

Answer:

237 K

Explanation:

Given that,

Initial temperature, T₁ = 201⁰C = 474 K

Let P be the initial pressure. Upon cooling the gas, the pressure decreases by a factor of 2.0, while the volume and the amount of gas remain constant.

Final pressure = P/2

The relation between the pressure and temperature is as follows :

\dfrac{P_1}{P_2}=\dfrac{T_1}{T_2}

Put all the known values,

\dfrac{P}{\dfrac{P}{2}}=\dfrac{474}{T_2}\\\\2=\dfrac{474}{T_2}\\\\T_2=\dfrac{474}{2}\\\\T_2=237\ K

So, the final temperature of the gas is equal to 237 K.

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The compounds n-butane, ch3(ch2)2ch3, and trimethylamine, n(ch3)3, have very similar molecular weights. However, their melting p
Ostrovityanka [42]
<h3>Answer:</h3>

            The lowest boiling point is of n-Butane because it only experiences London Dispersion Forces between molecules.

<h3>Explanation:</h3>

                   Lets take start with the melting point of both compounds.

                                      n-Butane  =  - 140 °C

                                      Trimethylamine  =  - 117 °C

Intermolecular Forces in n-Butane:

                                                      As we know n-Butane is made up of Carbon and Hydrogen atoms only bonded via single covalent bonds. The electronegativity difference between C and C atoms is zero while, that between C and H atoms is 0.35 which is less than 0.4. Hence, the bonds in n-Butane are purely non polar in nature. Therefore, only London Dispersion Forces are found in n-Butane which are considered as the weakest intermolecular interactions.

Intermolecular Forces in Trimethylamine:

                                                             Trimethylamine (a tertiary amine) is made up of Nitrogen, Carbon and Hydrogen atoms bonded via single covalent bonds. The electronegativity difference between N and C atoms is 0.49  which is greater than 0.4. Hence, the C-N bond is polar in nature. Therefore, Dipole-Dipole interactions will be formed along with London Dispersion Forces which are stronger than Dispersion Forces. Therefore, due to Dipole-Dipole interactions Trimethylamine will have greater melting point than n-Butane.

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4 years ago
How many grams of calcium are made up by 2.68 x 1023 atoms?
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Answer:

Mass = 17.8 g

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Number of atoms of Ca = 2.68 × 10²³

Mass in gram = ?

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Avogadro number:

The given problem will solve by using Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.

The number 6.022 × 10²³ is called Avogadro number.

1 mole = 6.022 × 10²³ atoms

2.68 × 10²³ atoms × 1 mole  /6.022 × 10²³ atoms

0.445 mol

Mass in gram;

Mass = number of moles ×  molar mass

Mass = 0.445 mol  ×  40 g/mol

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