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vichka [17]
3 years ago
8

Complete the concept map below.5 parts each only science​

Chemistry
1 answer:
Slav-nsk [51]3 years ago
4 0

Answer:

wheres the map? I can't see it even tho im using my eye glasses

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If the caffeine concentration in a particular brand of soda is 1.87 mg/oz, drinking how many cans of soda would be lethal? Assum
Drupady [299]
2.77mg caffeine / 1oz12oz / 1canLethal dose: 10.0g caffeine = 10,000mg caffeine First, find how much caffeine is in one can of soda, then divide that amount by the lethal dose to find the number of cans. (2.77mg caffeine / 1oz) * (12oz / 1can) = 33.24mg caffeine / 1can. (10,000mg caffeine) * (1can / 33.24mg caffeine) = 300.84 cans. Since we can't buy parts of a can of soda, then we have to round up to 301 cans. Notice how all the values were set up as ratios and how the units cancelled.
4 0
4 years ago
In Mexico, avocados are 39 pesos per kilogram. What is the cost in pesos of an
Tems11 [23]

Answer:

The correct answer is - 4.5 pesos.

Explanation:

Given:

rate of per kg = 39 pesos

price for 0.25 lb = ?

Solution:

we know and given that,

1 kg = 2.20 lb

1 lb = 1000gm/2.20

then, the price for 0.25 lb would be:

=> (39/2.20)*0.25

= 4.4318 or 4.5 pesos

7 0
3 years ago
At 20 ?C the vapor pressure of benzene (C6H6)is 75 torr, and that of toluene (C7H8) is 22 torr
tia_tia [17]

Answer:

(a) Benzene = 0.26; toluene = 0.74

(b) Benzene = 0.55

Explanation:

1. Calculate the composition of the solution

For convenience, let’s call benzene Component 1 and toluene Component 2.

According to Raoult’s Law,  

p_{1} = \chi_{1}p_{1}^{\circ}\\p_{2} = \chi_{2}p_{2}^{\circ}

where

p₁ and p₂ are the vapour pressures of the components above the solution

χ₁ and χ₂ are the mole fractions of the components

p₁° and p₂° are the vapour pressures of the pure components.

Note that

χ₁ + χ₂ = 1

So,  

\begin{array}{rcl}p_{\text{tot}} &=& p_{1} + p_{2}\\p_{\text{tot}} & = & \chi_{1}p_{1}^{\circ}  + (1 - \chi_{1})p_{2}^{\circ}\\36 & = & \chi_{1}\times 75  + (1 - \chi_{1}) \times 22 \\36 & = & 75\chi_{1} + 22 -22\chi_{1}\\14 & = & 53\chi_{1}\\\chi_{1} & = & \mathbf{0.26}\\\end{array}

χ₁ = 0.26 and χ₂ = 0.74

2. Calculate the mole fraction of benzene in the vapour

In the liquid,  

p₁ = χ₁p₁° = 0.26 × 75 mm = 20 mm

∴ In the vapour

\chi_{1} = \dfrac{p_{1}}{p_{\text{tot}} } = \dfrac{\text{20 mm} }{\text{36 mm}}  = 0.55

Note that the vapour composition diagram below has toluene along the horizontal axis. The purple line is the vapour pressure curve for the vapour. Since χ₂ has dropped to 0.45, χ₁ has increased to 0.55.

7 0
3 years ago
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Neko [114]
<span>SnSO4 • 7H2O
This formula has 2 part 
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So full name is </span><span> tin (II) sulfate heptahydrate.</span>
6 0
3 years ago
Which side does the light always start from?
jarptica [38.1K]

Answer:

in prism

it's from the rectangular reflecting surface

7 0
2 years ago
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