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Andreyy89
3 years ago
14

What is an orbital?

Chemistry
1 answer:
Alika [10]3 years ago
4 0
Is a mathematical function describing the location and wave
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NemiM [27]
The given formula for heat, Q=mc(Tf-Ti), is the best way to solve such problems with changes in temperature. It can be said that m is the mass of the substance. C is the specific heat of the substance. The term (Tf-Ti) is the change in temperature.

Q = mc(Tf-Ti) = 480g(0.96 J/g-C)(234-22) = 97689.6 Joules of heat
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3 years ago
20 N force moving a box to 30 meters distance. How much work id done? if it takes 10 sec to do this work, how much power is used
dalvyx [7]

Answer:

Work done = 600 J

Power used = 60 W

Explanation:

Given:

Force acting on the box is, F=20\ N

Displacement of the box is, S=30\ m

Time taken for the work, t=10\ s

Now, we know that, work is said to be done by a force only when there is displacement caused by the force in its direction.

Here, the force acting on the box causes a displacement of 30 m in its direction. So, work done is equal to the product of force and displacement caused.

Therefore, work done on the box is given as:

Work=Force\times Displacement\\Work=F\times S\\Work=(20\ N)\times (30\ m)\\Work=600\ J

Therefore, the work done is 600 J.

Now, we know that, power is given as work done per unit time.

So, power used is given as:

Power=\frac{Work}{Time}\\\\Power=\frac{600\ J}{10\ s}\\\\Power=60\ W

Therefore, the power used is 60 W.

5 0
3 years ago
What causes ocean water near the equator to be warmer than ocean water farther north
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Because the water near the equator gets more direct sunlight.
6 0
3 years ago
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If 5.100 g of c6h6 is burned and the heat produced from the burning is added to 5691 g of water at 21 °c, what is the final temp
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  <span>C6H12 = 6x12 + 6x1 = 78. 
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Using proportions you can then calculate that 
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x = 331.3kJ = 331300J. 

heat = mass x ΔT x 4.18J/g° 
ΔT = 331300J / (5691g x 4.18J/g°) = 13.9° 

final temp = 21 + 14° = 35°C</span>
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4 years ago
The empirical formula for a compound that is 1.2% h, 42.0%cl, and 56.8%o is
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Hope you understand how to work out those types of questions now xD ;)

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