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salantis [7]
3 years ago
7

The diameter of a circle is 36 centimeters. What is the circle's area?

Mathematics
1 answer:
PilotLPTM [1.2K]3 years ago
6 0

Answer:

1017.88

Step-by-step explanation:

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I really need help with this problem steps
melamori03 [73]
Solve for y by setting one equation =to X after that you can substitute the equation into the other one let's set the first one in X= FORM
X-7y=10
-2x+14y=-20

Add 7y to both sides of the first equation to let x stand alone
X=7y+10
Now you can substitute x on the second equation
-2 (7y+10)+14y=-20
Distribute
-14y-20+14y=-20
Add and simplify
Us cancel out =0
-20=-20
0=0
They are the same equations you can also divide the second equation by -2 which would make it look like this
X-7y=10
-2 (x-7y=10)
Let me know if I have answered your question
5 0
3 years ago
Water comes out of a pipe at a rate of 30 gallons per minute.
Lyrx [107]

Answer:

90

Step-by-step explanation:

30x3=90

3 0
3 years ago
Read 2 more answers
Hello i need help on all 3 of these if you could
adell [148]

Answer:oh okay

Step-by-step explanation:

4 0
3 years ago
<img src="https://tex.z-dn.net/?f=%5Csf%206x%2B4y-2x" id="TexFormula1" title="\sf 6x+4y-2x" alt="\sf 6x+4y-2x" align="absmiddle"
tangare [24]
Not sure what form you want this in:

Simplified this is 4x+4y

Factorised this is 4(x+y)

3 0
3 years ago
Read 2 more answers
] It is claimed that 42% of US college graduates had a mentor in college. For a sample of college graduates in Colorado, it was
Bad White [126]

Answer:

z=\frac{0.480 -0.42}{\sqrt{\frac{0.42(1-0.42)}{1045}}}=3.930  

The p value for this case would be given by:

p_v =P(z>3.930)=0.0000443  

For this case the p value is lower than the significance level so then we have enough evidence to reject the null hypothesis so then we can conclude that the true proportion is significantly higher than 0.42

Step-by-step explanation:

Information given

n=1045 represent the random sample selected

X=502 represent the college graduates with a mentor

\hat p=\frac{502}{1045}=0.480 estimated proportion of college graduates with a mentor

p_o=0.42 is the value that we want to test

z would represent the statistic

p_v represent the p value

Hypothesis to test

We want to test if the true proportion is higher than 0.42, the system of hypothesis are.:  

Null hypothesis:p \leq 0.42  

Alternative hypothesis:p > 0.42  

The statistic is given by:

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

Replacing the info we got:

z=\frac{0.480 -0.42}{\sqrt{\frac{0.42(1-0.42)}{1045}}}=3.930  

The p value for this case would be given by:

p_v =P(z>3.930)=0.0000443  

For this case the p value is lower than the significance level so then we have enough evidence to reject the null hypothesis so then we can conclude that the true proportion is significantly higher than 0.42

7 0
3 years ago
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