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solong [7]
3 years ago
8

Which matrix equation can be used to solve the system? (2x+ 5y = 15 X + 3y = 18

Mathematics
2 answers:
Gnesinka [82]3 years ago
8 0

Answer:

option 3

Step-by-step explanation:

AX = B\\X = A^{-1}B\\\\A = \left[\begin{array}{CC}\\2&5\\1&3\end{array}\right]\\\\\\B =\left[\begin{array}{C}\\15&18\end{array}\right]\\\\\\X =\left[\begin{array}{C}\\x&y\end{array}\right]

det A = 1\\\\adj A = \left[\begin{array}{CC}\\3&-5\\-1&2\end{array}\right]

A^{-1} = \frac{1}{det A} \times Adj A

      = 1 \times \left[\begin{array}{CC}\\3&-5\\-1&2\end{array}\right]\\\\\\=  \left[\begin{array}{CC}\\3&-5\\-1&2\end{array}\right]

Therefore,

      X = A^{-1}B\\\\\\\left[\begin{array}{C}\\x&y\end{array}\right]  =  \left[\begin{array}{CC}\\3&-5\\-1&2\end{array}\right]\left[\begin{array}{C}\\15&18\end{array}\right]\\\\\\

pychu [463]3 years ago
3 0

THE CORRECT OPTION IS A where the input data is correct

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4 years ago
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3 years ago
Question is below (wasn't sure about the answer)
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Answer: Choice A)

H = \frac{SA}{2(L+W)} - \frac{LW}{L+W}\\\\

=================================================

Work Shown:

SA = 2(LW + LH + HW)\\\\2(LW + LH + HW) = SA\\\\LW + LH + HW = \frac{SA}{2}\\\\LH + HW = \frac{SA}{2} - LW\\\\H(L + W) = \frac{SA}{2} - LW\\\\H = \frac{\frac{SA}{2} - LW}{(L + W)}\\\\H = \frac{SA}{2(L+W)} - \frac{LW}{L+W}\\\\

This is not the only way to solve for H.

3 0
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