No, because the input repeated 4 twice and the output repeated 3 twice
The probability that both grab oranges would be = 
Step-by-step explanation:
Given,
A bowl contains,
Apples = a = 5
Oranges = o = 2
bananas = b = 2
Total fruits in bowl = x = a + o + b = 5 + 2 + 2 = 9
Now, Christian and Aaron come home from school and randomly grab one fruit each.
The probability of first selecting orange would be = 
Now, the oranges left would be 2 - 1 = 1
and total fruits would be = 9 - 1 = 8
Hence, the probability of selecting second orange would be = 
Therefore, the probability that both grab oranges would be = 
the formula is a_{1}+(n-1) d
so a_{1} would be the first number in the sequence, which would be 13 in problem 9.
13+(n-1)d
then you put in n, which is 10 (it represents which number in the sequence you're looking for, for example 16 is the second number in the sequence)
13+(10-1)d
then you find the difference between each number, represented by d which in this case is 3
13+(10-1)3
13+(9)3
13+27=
40