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stira [4]
3 years ago
9

What is the area of a triangle whose vertices are D(3, 3), E(3, −1), and F(−2, −5)?

Mathematics
1 answer:
yulyashka [42]3 years ago
6 0

Answer:

10 units²

Step-by-step explanation:

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Given: A cuboid with the dimesion below:

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The formula for finding the surface area of a cuboid is given as:

A_{\text{Cuboid Surface Area}}=2(l\times w+l\times h+w\times h)

From the diagram, it can be seen that

\begin{gathered} l=\text{length}=5\operatorname{cm} \\ w=\text{width}=4\operatorname{cm} \\ h=\text{height}=5\operatorname{cm} \end{gathered}

Substitute the given into the formula as shown below:

\begin{gathered} A_{\text{Cuboid Surface Area}}=2(l\times w+l\times h+w\times h) \\ A_{\text{Cuboid Surface Area}}=2(5cm\times4cm+5cm\times5cm+4cm\times5cm) \\ A_{\text{Cuboid Surface Area}}=2(20cm^2+25cm^2+20cm^2) \\ A_{\text{Cuboid Surface Area}}=2(65\operatorname{cm}^2) \\ A_{\text{Cuboid Surface Area}}=130\operatorname{cm}^2 \end{gathered}

Hence, the surface area of the given cuboid is 130cm²

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Step-by-step explanation:

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